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es6 reduce return promise

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Lonely Lizard answered on April 4, 2020 Popularity 9/10 Helpfulness 3/10

answer es6 reduce return promise

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es6 reduce return promise

Comment

async function slowCounter () {
    const ret = await ([100, 200, 300, 400, 500]).reduce(
        async (promise, wait, idx) => {
            return promise.then(async last => {
                const ret = last + wait
                console.log(`${idx}: waiting ${wait}ms to return ${ret}`)
                await new Promise((res, rej) => setTimeout(res, wait))
                return ret
            })
        }, Promise.resolve(0))
    console.log(ret)
}

slowCounter ()

Popularity 9/10 Helpfulness 3/10 Language javascript

Source: stackoverflow.com

Tags: javascript promise reduce return

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Contributed on Sep 01 2020

Lonely Lizard

0 Answers Avg Quality 2/10

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javascript reduce promises

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const sum = await [
  Promise.resolve(1),
  Promise.resolve(1),
  Promise.resolve(1)
].reduce(async (previousPromise, itemPromise) => {
  const sum = await previousPromise;
  const item = await itemPromise;
  return sum + item;
}, Promise.resolve(0))

// sum === 3

Popularity 9/10 Helpfulness 4/10 Language javascript

Source: Grepper

Tags: javascript j

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Contributed on Apr 04 2020

Gifted Gerenuk

0 Answers Avg Quality 2/10

javascript reduce return array

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var store = [0, 1, 2, 3, 4];

var stored = store.reduce(function(pV, cV, cI){
  console.log("pv: ", pV);
  pV.push(cV);
  return pV; // *********  Important ******
}, []);

Popularity 8/10 Helpfulness 3/10 Language javascript

Source: stackoverflow.com

Tags: javascript j

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Contributed on Oct 11 2022

Anh Tuan Pham

0 Answers Avg Quality 2/10

es6 reduce return promise

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es6 reduce return promise

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