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df.iterrows()

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Encouraging Echidna answered on April 1, 2020 Popularity 10/10 Helpfulness 6/10

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df.iterrows()

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import pandas as pd
import numpy as np

df = pd.DataFrame({'c1': [10, 11, 12], 'c2': [100, 110, 120]})

for index, row in df.iterrows():
    print(row['c1'], row['c2'])

Popularity 10/10 Helpfulness 6/10 Language python

Source: stackoverflow.com

Tags: python

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Contributed on Sep 20 2020

Encouraging Echidna

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for index, row in df.iterrows():
    print(row['c1'], row['c2'])

Popularity 10/10 Helpfulness 2/10 Language python

Source: Grepper

Tags: python py

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Contributed on Jun 29 2020

nomjeeb

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iterrows pandas

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>>> df = pd.DataFrame([[1, 1.5]], columns=['int', 'float'])
>>> row = next(df.iterrows())[1]
>>> row
int      1.0
float    1.5
Name: 0, dtype: float64
>>> print(row['int'].dtype)
float64
>>> print(df['int'].dtype)
int64

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Source: pandas.pydata.org

Tags: pandas pa

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Contributed on Apr 01 2020

Filthy Flatworm

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