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The Bowtie Bandit answered on October 1, 2020 Popularity 10/10 Helpfulness 3/10

answer reduce

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reduce

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// Array.prototype.reduce()

const array1 = [1, 2, 3, 4];
const reducer = (accumulator, currentValue) => accumulator + currentValue;

// 1 + 2 + 3 + 4
console.log(array1.reduce(reducer));
// expected output: 10

// 5 + 1 + 2 + 3 + 4
console.log(array1.reduce(reducer, 5));
// expected output: 15

Popularity 10/10 Helpfulness 3/10 Language javascript

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Contributed on Oct 01 2020

The Bowtie Bandit

0 Answers Avg Quality 2/10

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reduce javascript

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let array = [36, 25, 6, 15];
 
array.reduce((acc, curr) => acc + curr, 0)
// 36 + 25 + 6 + 15 = 82

Popularity 10/10 Helpfulness 4/10 Language javascript

Source: Grepper

Tags: javascript j

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Contributed on Jul 05 2022

Rick Oburu

0 Answers Avg Quality 2/10

reduce()

Comment

const array1 = [1, 2, 3, 4];
const reducer = (accumulator, currentValue) => accumulator + currentValue;

// 1 + 2 + 3 + 4
console.log(array1.reduce(reducer));
// expected output: 10

// 5 + 1 + 2 + 3 + 4
console.log(array1.reduce(reducer, 5));
// expected output: 15

Popularity 10/10 Helpfulness 4/10 Language javascript

Source: developer.mozilla.org

Tags: javascript j

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Contributed on Jan 17 2021

putsan

0 Answers Avg Quality 2/10

A.reduce

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const arr = [3, 5, 4, 11, 7, 22];

arr.reduce((previousValue, currentValue) => {
    return previousValue + currentValue;  // <--- 3 + 5 + 4 + 11 + 7 + 22 = 52
}, 0)

Popularity 10/10 Helpfulness 4/10 Language javascript

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Tags: javascript j

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Contributed on Aug 06 2022

The Stanliest Stanley

0 Answers Avg Quality 2/10

reduce javascript

Comment

var depthArray = [1, 2, [3, 4], 5, 6, [7, 8, 9]];

depthArray.reduce(function(flatOutput, depthItem) {
    return flatOutput.concat(depthItem);
}, []);

=> [1, 2, 3, 4, 5, 6, 7, 8, 9];


// --------------
const prices = [100, 200, 300, 400, 500];
const total = prices.reduce((total, cur) => {return total + cur} )
//  init value = 0 => total = 1500;


// --------------
const prices = [100, 200, 300, 400, 500];
const total = prices.reduce(function (total, cur) => {
                   return total + cur
                }, 1 )
// init value = 1 => so when plus all numnber will be result => 1501;

// --------------
const prices = [100, 200, 300, 400, 500];
const total = prices.reduce((total, cur) => total + cur )
// 1500;

Popularity 10/10 Helpfulness 4/10 Language javascript

Source: Grepper

Tags: javascript j

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Contributed on Mar 03 2022

Zidane (Vi Ly - VietNam)

0 Answers Avg Quality 2/10

reduce in js

Comment

Reduce in js

let arr=[5,6,2];
let sum=arr.reduce((accumulator,current,index,arr)=>{
   return accumulator+=current;
});
console.log(sum);//5+6+13

accumulator acumulate(hold) the sum output

reduce methood creat a new array and does not change actual array

Popularity 10/10 Helpfulness 3/10 Language javascript

Source: Grepper

Tags: javascript j

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Contributed on May 19 2023

pabel reja

0 Answers Avg Quality 2/10

reduce in js

Comment

n JavaScript, the reduce() method is used to apply a function to each element of an array and reduce it to a single value. The reduce() method takes two parameters: a callback function and an optional initial value.

Here is the basic syntax of the reduce() method:

'array.reduce(callback, initialValue)'

The callback function takes four parameters: accumulator, currentValue, currentIndex, and array. The accumulator is the value returned from the previous invocation of the callback, or the initialValue if provided. The currentValue is the current element being processed, currentIndex is the index of the current element, and array is the array on which reduce() was called.

The reduce() method executes the callback function once for each element in the array (excluding the initial value if provided), and the return value of the callback becomes the new value of the accumulator.

Here is an example that demonstrates the usage of reduce() to calculate the sum of an array of numbers:

const numbers = [1, 2, 3, 4, 5];

const sum = numbers.reduce((accumulator, currentValue) => {
  return accumulator + currentValue;
}, 0);

console.log(sum); // Output: 15


In the example above, the reduce() method is called on the numbers array. The callback function takes two parameters, accumulator and currentValue, and simply adds them together. The initial value of the accumulator is set to 0 using the second argument of reduce(). The final result, 15, is the sum of all the numbers in the array.

Popularity 10/10 Helpfulness 2/10 Language javascript

Source: Grepper

Tags: javascript j

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Contributed on Jun 19 2023

Strange Shrew

0 Answers Avg Quality 2/10

reduce javascript

Comment

 let sum = arr.reduce((curr, index) => curr + index);

Popularity 10/10 Helpfulness 2/10 Language javascript

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Tags: javascript j

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Contributed on Dec 24 2020

Frightened Frog

0 Answers Avg Quality 2/10

Reduce use

Comment

//Array Reduce
let arr=[12,14,15,28]
let numarr=arr.reduce((h1,h2)=>{
  return h1+h2
})
console.log(numarr)

Popularity 10/10 Helpfulness 2/10 Language javascript

Source: replit.com

Tags: javascript j

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Contributed on Sep 05 2022

Fragile Flatworm

0 Answers Avg Quality 2/10

reduce in js

Comment

reduce in js with a previous accumulator value

var array = [36, 25, 6, 15];

var p=array.reduce(function(accumulator, currentValue,index,arr) {
  return accumulator+=currentValue;
},8); // 36 + 25 + 6 + 15 = 82
 console.log(p);

here accumulator previously accumulate value 8

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Tags: javascript j

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Contributed on May 19 2023

pabel reja

0 Answers Avg Quality 2/10

reduce

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