python meanGroups(a):

lost_cause answered on November 6, 2020 Popularity 3/10 Helpfulness 2/10

answer python meanGroups(a):

python meanGroups(a):

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def meanGroups(a):
    d = []
    e = []
    for i, j in enumerate(a):
        if sum(j) / len(j) not in e:
            e += [sum(j) / len(j)]
            d += [[i]]
        else:
            d[e.index(sum(j) / len(j))] += [i]
    return d

Popularity 3/10 Helpfulness 2/10 Language python

Source: Grepper

Tags: python

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Contributed on Nov 06 2020

lost_cause

0 Answers Avg Quality 2/10

python meanGroups(a):

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