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shell script to check the directory exists

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Alive Armadillo answered on October 22, 2020 Popularity 10/10 Helpfulness 10/10

answer shell script to check the directory exists

related linux command if directory exists

related Check is directory exist shell

related How can I check if a directory exists in a Bash shell script?

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shell script to check the directory exists

Comment

Directory="/opt"
if [ -d "$Directory" ];
then
	echo -e "it's exits\n"
fi
### To check if it's not exists
if [ ! -d "$Directory" ];
then 
	echo -e "It's not there\n"
fi

Popularity 10/10 Helpfulness 10/10 Language shell

Source: stackoverflow.com

Tags: directory exists script shell

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Contributed on Dec 31 2020

Alive Armadillo

0 Answers Avg Quality 2/10

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linux command if directory exists

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DIR="/etc/httpd/"
if [ -d "$DIR" ]; then
  ### Take action if $DIR exists ###
  echo "Installing config files in ${DIR}..."
else
  ###  Control will jump here if $DIR does NOT exists ###
  echo "Error: ${DIR} not found. Can not continue."
  exit 1
fi

Popularity 10/10 Helpfulness 7/10 Language shell

Source: www.cyberciti.biz

Tags: command

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Contributed on Oct 22 2020

Clumsy Cassowary

0 Answers Avg Quality 2/10

Check is directory exist shell

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DIR="/etc/httpd/"
if [ -d "$DIR" ]; then
  # Take action if $DIR exists. #
  echo "Installing config files in ${DIR}..."
fi

Popularity 10/10 Helpfulness 3/10 Language csharp

Source: www.cyberciti.biz

Tags: c# c

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Contributed on Jun 02 2021

Nervous Newt

0 Answers Avg Quality 2/10

How can I check if a directory exists in a Bash shell script?

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To check if a directory exists in a shell script, you can use the following:

if [ -d "$DIRECTORY" ]; then
  # Control will enter here if $DIRECTORY exists.
fi
Or to check if a directory doesn't exist:

if [ ! -d "$DIRECTORY" ]; then
  # Control will enter here if $DIRECTORY doesn't exist.
fi
However, as Jon Ericson points out, subsequent commands may not work as intended if you do not take into account that a symbolic link to a directory will also pass this check. E.g. running this:

ln -s "$ACTUAL_DIR" "$SYMLINK"
if [ -d "$SYMLINK" ]; then 
  rmdir "$SYMLINK" 
fi
Will produce the error message:

rmdir: failed to remove `symlink': Not a directory
So symbolic links may have to be treated differently, if subsequent commands expect directories:

if [ -d "$LINK_OR_DIR" ]; then 
  if [ -L "$LINK_OR_DIR" ]; then
    # It is a symlink!
    # Symbolic link specific commands go here.
    rm "$LINK_OR_DIR"
  else
    # It's a directory!
    # Directory command goes here.
    rmdir "$LINK_OR_DIR"
  fi
fi
Take particular note of the double-quotes used to wrap the variables. The reason for this is explained by 8jean in another answer.

If the variables contain spaces or other unusual characters it will probably cause the script to fail.

Popularity 10/10 Helpfulness 3/10 Language shell

Source: stackoverflow.com

Tags: bash

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Contributed on Feb 05 2022

shafeeque

0 Answers Avg Quality 2/10

check if directory exists bash

Comment

#!/bin/bash

directory="/path/to/directory"

# Check if directory exists
if [ -d "$directory" ]; then
  echo "Directory exists"
else
  echo "Directory does not exist"
fi

Popularity 9/10 Helpfulness 3/10 Language shell

Source: Grepper

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Contributed on Sep 12 2023

YOU.com

0 Answers Avg Quality 2/10

shell script to check the directory exists

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