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python compare lists unordered

Anxious Axolotl answered on January 13, 2021 Popularity 7/10 Helpfulness 2/10

answer python compare lists unordered

related how to compare two unordered lists in python

python compare lists unordered

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def compare(s, t):
    return sorted(s) == sorted(t)

Popularity 7/10 Helpfulness 2/10 Language typescript

Source: stackoverflow.com

Tags: compare python typescript unordered

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Contributed on Jan 13 2021

Anxious Axolotl

0 Answers Avg Quality 2/10

Closely Related Answers

how to compare two unordered lists in python

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# O(n): The Counter() method is best (if your objects are hashable):
def compare(s, t):
    return Counter(s) == Counter(t)

# O(n log n): The sorted() method is next best (if your objects are orderable):
def compare(s, t):
    return sorted(s) == sorted(t)
  
# O(n * n): If the objects are neither hashable,
# nor orderable, you can use equality:
def compare(s, t):
    t = list(t)   # make a mutable copy
    try:
        for elem in s:
            t.remove(elem)
    except ValueError:
        return False
    return not t

Popularity 5/10 Helpfulness 1/10 Language python

Source: stackoverflow.com

Tags: compare python unordered

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