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leap year algorithm

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Marton answered on February 18, 2021 Popularity 10/10 Helpfulness 6/10

answer leap year algorithm

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leap year algorithm

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def isLeapYear (year):
    if ((year % 4 == 0) and (year % 100 != 0)) or (year % 400 == 0):
		true
    else:
    	false

Popularity 10/10 Helpfulness 6/10 Language python

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Contributed on Feb 18 2021

Marton

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leap year algorithm

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if year % 4 == 0:
  if year % 100 == 0:
    if year % 400 == 0:
      print("leap year")
    else:
      print("not a leap year")
  else:
    print("leap year")
else:
  print("not a leap year")

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Contributed on Apr 30 2021

Cautious Capuchin

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Leap year program

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#include <stdio.h>

int main() {
   int year;
   year = 2016;

   if (((year % 4 == 0) && (year % 100!= 0)) || (year%400 == 0))
      printf("%d is a leap year", year);
   else
      printf("%d is not a leap year", year);

   return 0;
}

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Source: www.tutorialspoint.com

Tags: leap-year leap

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Contributed on Oct 20 2021

Amused Ant

0 Answers Avg Quality 2/10

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