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binary search tree in python

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Aggressive Albatross answered on March 29, 2021 Popularity 10/10 Helpfulness 2/10

answer binary search tree in python

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binary search tree in python

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Binary Search Tree at this link:
  
https://github.com/shreyasvedpathak/Data-Structure-Python/tree/master/BinaryTrees

Popularity 10/10 Helpfulness 2/10 Language python

Source: Grepper

Tags: binary-search-tree python

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Contributed on Mar 29 2021

Aggressive Albatross

0 Answers Avg Quality 2/10

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python binary tree

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class Binarytree:
    def __init__(self, node):
        """

       :param node: root node
       """
        self.node = node
        self.left = None
        self.right = None

    def add_node(self, node):
        """

       :param node: append node
       :return: None
       """
        if node == self.node:
            return

        if node < self.node:
            if self.left:
                self.left.add_node(node)
            else:
                self.left = Binarytree(node)
        else:
            if self.right:
                self.right.add_node(node)
            else:
                self.right = Binarytree(node)

    def search(self, val):
        """

       :param val: value to search in binary tree
       :return: True if found else False
       """
        if val == self.node:
            return True
        if val < self.node:
            if self.left:
                return self.left.search(val)
            else:
                return False
        else:
            if self.right:
                return self.right.search(val)
            else:
                return False

    def print_nodes(self):
        """
        print all node values to console window
       :return: None
       """

        if self.left:
            self.left.print_nodes()

        print(self.node)

        if self.right:
            self.right.print_nodes()

        return False


def build_tree(node):
    """

   :param node: list of nodes
   :return: Binarytree with nodes
   """
    root = Binarytree(node[0])
    for i in range(1, len(node)):
        root.add_node(node[i])
    return root


if __name__ == '__main__':
    nodes = [30, 10, 40, 22, 15, 18]
    tree = build_tree(nodes)
    tree.add_node(18)
    tree.add_node(20)
    print("15 found in binary tree", tree.search(15))
    print("100 found in binary tree", tree.search(100))
    tree.print_nodes()

Popularity 9/10 Helpfulness 4/10 Language python

Source: codefreelance.net

Tags: binary-tree bina

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Contributed on Sep 06 2022

Jerome Scott

0 Answers Avg Quality 2/10

code to printing a binary search tree in python

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class BSTNode:
    def __init__(self, key=None):
        self.left = None
        self.right = None
        self.key = key
# Insert method can add a list of nodes to the BST
    def insert(self, keyList):
       for i in keyList:
          self.insertKey(i)
# This insertKey 
    def insertKey(self, key):
        if not self.key:
            self.key = key
            return
        if self.key == key:
            return
        if key < self.key:
            if self.left:
                self.left.insertKey(key)
                return
            self.left = BSTNode(key)
            return
        if self.right:
            self.right.insertKey(key)
            return
        self.right = BSTNode(key)
    def display(self):
        lines, *_ = self._display_aux()
        for line in lines:
            print(line)

    def _display_aux(self):
        """Returns list of strings, width, height, and horizontal coordinate of the root."""
        # No child.
        if self.right is None and self.left is None:
            line = '%s' % self.key
            width = len(line)
            height = 1
            middle = width // 2
            return [line], width, height, middle

        # Only left child.
        if self.right is None:
            lines, n, p, x = self.left._display_aux()
            s = '%s' % self.key
            u = len(s)
            first_line = (x + 1) * ' ' + (n - x - 1) * '_' + s
            second_line = x * ' ' + '/' + (n - x - 1 + u) * ' '
            shifted_lines = [line + u * ' ' for line in lines]
            return [first_line, second_line] + shifted_lines, n + u, p + 2, n + u // 2

        # Only right child.
        if self.left is None:
            lines, n, p, x = self.right._display_aux()
            s = '%s' % self.key
            u = len(s)
            first_line = s + x * '_' + (n - x) * ' '
            second_line = (u + x) * ' ' + '\\' + (n - x - 1) * ' '
            shifted_lines = [u * ' ' + line for line in lines]
            return [first_line, second_line] + shifted_lines, n + u, p + 2, u // 2

        # Two children.
        left, n, p, x = self.left._display_aux()
        right, m, q, y = self.right._display_aux()
        s = '%s' % self.key
        u = len(s)
        first_line = (x + 1) * ' ' + (n - x - 1) * '_' + s + y * '_' + (m - y) * ' '
        second_line = x * ' ' + '/' + (n - x - 1 + u + y) * ' ' + '\\' + (m - y - 1) * ' '
        if p < q:
            left += [n * ' '] * (q - p)
        elif q < p:
            right += [m * ' '] * (p - q)
        zipped_lines = zip(left, right)
        lines = [first_line, second_line] + [a + u * ' ' + b for a, b in zipped_lines]
        return lines, n + m + u, max(p, q) + 2, n + u // 2
    #Inorder Walk    
    def inorder(self):
        if self.left:
            self.left.inorder()
        print(self.key)
        if self.right:
            self.right.inorder()
a = BSTNode()
a.insert([5,7,4,3,5,1,3,6]) #inserting some random numbers in the form of list
a.inorder()
a.display()

Popularity 9/10 Helpfulness 3/10 Language python

Source: stackoverflow.com

Tags: binary-search-tree binary-search-tre

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Contributed on Mar 15 2022

Poised Panda

0 Answers Avg Quality 2/10

python binary tree search

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def search(node, search_item):

    # Base case for recursion:
    # The recursion will stop if the search item has been found
    if search_item == node.data:
        return True

    # Check if the search item is greater than the node data
    # and there is another node to the right to check
    elif search_item > node.data and node.right is not None:
        return search(node.right, search_item)

    # Check if the search item is less than the node data
    # and there is another node to the left to check
    elif search_item < node.data and node.left is not None:
        return search(node.left, search_item)

    # Otherwise the search item does not exist
    else:
        return False

Popularity 8/10 Helpfulness 2/10 Language python

Source: isaaccomputerscience.org

Tags: python

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Contributed on Sep 20 2022

Combative Caribou

0 Answers Avg Quality 2/10

Binary Search tree implementation in python

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"""
	              17
		    /    \
		   /      \
		  /	   \		  
		 4         20
		/\	   /\	
	       /  \       /  \
	      /    \     /    \
	     1      9   18    23
			        \
				 \
				  \ 
				   34
							 
"""							 

# Binary Search Tree implementation in Python

class BinaryTreeNode():
    def __init__(self, data):
        self.data = data
        self.left = None
        self.right = None
        
    def add_child(self, data):
        if data == self.data: # check if the of new data exist already in the tree, if yes don't add
            return
        
        if data < self.data:
            # Add to left subtree
            if self.left:
                self.left.add_child(data) # Recursively call the add_child method to add the data to an appropriate place
            else:
                self.left = BinaryTreeNode(data)
        else:
            # Add to right subtree
            if self.right:
                self.right.add_child(data) # Recursively call the add_child method to add the data to an appropriate place
            else:
                self.right = BinaryTreeNode(data)
    
    # Visit Left subtree, then Root node and finaly Right subtree
    def in_order_traversal(self):  # Left - Root - Right
        elements = []
        
        # Getting all elements of the Left Subtree    
        if self.left:
            elements += self.left.in_order_traversal() # Recursively get all the elements of the left subtree and add them into the list
        elements.append(self.data) # Adding the root node to the list
        
        # Getting all elements of the Right Subtree    
        if self.right:
            elements += self.right.in_order_traversal() # Recursively get all the elements of the right subtree and add them into the list
        return elements
        
    # Get all elements from the Root node then the left subtree and finanally the Right subtree 
    def pre_order_traversal(self): # Root - Left - Right
        elements = []
        
        elements.append(self.data)
        
        if self.left:
            elements += self.left.pre_order_traversal()  # Recursively get all the elements of the left subtree and add them into the list
        
        if self.right:
            elements += self.right.pre_order_traversal()  # Recursively get all the elements of the right subtree and add them into the list

        
        return elements # get the Root node element
        
    # Get all elements from the Right subtree then the left subtree and finally the Root node    
    def post_order_traversal(self):
        elements = []
        
        if self.left:
            elements += self.left.post_order_traversal()  # Recursively get all the elements of the left subtree and add them into the list
        
        if self.right:
            elements += self.right.post_order_traversal()  # Recursively get all the elements of the right subtree and add them into the list
            
        elements.append(self.data) # Get the Root node element
        
        return elements
        
        
    def search_element(self, elem): # complexity of log n O(log n)
        if self.data == elem:
            return True
        elif elem < self.data:
            # This means if present, element would be on the left 
            if self.left:
               return self.left.search_element(elem)  
            else:
                return False
            
        else:
            # This means if present, element would be on the right
            if self.right:
                return self.right.search_element(elem)  
            else:
                return False
    
    
    def sum_of_all_elements_in_tree(self):
        return sum(self.in_order_traversal())
        
    def max_element_in_tree(self):
        return max(self.in_order_traversal())    
    
    def min_element_in_tree(self):
        return min(self.in_order_traversal())    
    
    
# Tree Builder helper method
def build_binary_tree(lst_elem: list):
    if len(lst_elem) >1:
        root_node = BinaryTreeNode(lst_elem[0])
        for i in lst_elem[1:]:
            root_node.add_child(i)
       
        #root_node.search_element(20)
        #print(root_node.in_order_traversal())
        return root_node
    else:
        return print("Insufficient number of elements")
        

if __name__ == '__main__':
   mt = build_binary_tree([17, -5, 4, 1, 20, 9, -1, 23, 18, 0, 34])
   print("In Order Traversal", mt.in_order_traversal())
   print("Post Order Traversal", mt.post_order_traversal())
   print("Pre Order Traversal", mt.pre_order_traversal())
   print(mt.search_element(20))
   print("Sum of all elemnts in tree", mt.sum_of_all_elements_in_tree())
   print("Max element in tree is", mt.max_element_in_tree())
   print("Min element in tree is", mt.min_element_in_tree())

Popularity 9/10 Helpfulness 2/10 Language python

Source: raw.githubusercontent.com

Tags: binary-search-tree binary-search-tre

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Contributed on Dec 28 2021

Vad

0 Answers Avg Quality 2/10

binary tree in python

Comment

-2

Binary Tree implementation at this link:
  
https://github.com/shreyasvedpathak/Data-Structure-Python/tree/master/BinaryTrees

Popularity 10/10 Helpfulness 2/10 Language python

Source: Grepper

Tags: binary-tree bina

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Contributed on Mar 29 2021

Aggressive Albatross

0 Answers Avg Quality 2/10

implementation of binary search tree in python

Comment

# Python program to demonstrate
# insert operation in binary search tree
 
# A utility class that represents
# an individual node in a BST
 
 
class Node:
    def __init__(self, key):
        self.left = None
        self.right = None
        self.val = key
 
# A utility function to insert
# a new node with the given key
 
 
def insert(root, key):
    if root is None:
        return Node(key)
    else:
        if root.val == key:
            return root
        elif root.val < key:
            root.right = insert(root.right, key)
        else:
            root.left = insert(root.left, key)
    return root
 
# A utility function to do inorder tree traversal
 
 
def inorder(root):
    if root:
        inorder(root.left)
        print(root.val)
        inorder(root.right)
 
 
# Driver program to test the above functions
# Let us create the following BST
#    50
#  /     \
# 30     70
#  / \ / \
# 20 40 60 80
 
r = Node(50)
r = insert(r, 30)
r = insert(r, 20)
r = insert(r, 40)
r = insert(r, 70)
r = insert(r, 60)
r = insert(r, 80)
 
# Print inoder traversal of the BST
inorder(r)

Popularity 8/10 Helpfulness 1/10 Language python

Source: www.geeksforgeeks.org

Tags: binary-search-tree binary-search-tre

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Contributed on Jun 28 2022

Ramesh Patel

0 Answers Avg Quality 2/10

binary search tree in python

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