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list_a = ["Hello", 2, 15, "World", 34] #just the array
number_of_elements = len(list_a)
print("Number of elements in the list: ", number_of_elements)
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list1 = [2,3,4,3,10,3,5,6,3]
elm_count = list1.count(3)
print('The count of element: 3 is ', elm_count)
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# Basic syntax:
# Using list comprehension:
sum([len(elem) for elem in list_of_lists])
# Example usage:
# Say you want to count the number of elements in a nested list like:
nested_list = [ [1, 2, 3, 45, 6, 7],
[22, 33, 44, 55],
[11, 13, 14, 15] ]
sum([len(elem) for elem in nested_list])
--> 14
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# List of strings
listOfElems = ['Hello', 'Ok', 'is', 'Ok', 'test', 'this', 'is', 'a', 'test']
len(s)
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mylist = ["abc", "def", "ghi", "jkl", "mno", "pqr"]
print(len(mylist))
# output 6
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List = ["Elephant", "Snake", "Penguin"]
print(len(List))
# With the 'len' function Python counts the amount of elements
# in a list (The length of the list).
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from collections import Counter
thelist = [1, 4, 2, 3, 5, 4, 5, 6, 7, 8, 1, 3, 4, 5, 9, 10, 11]
c = Counter(thelist)
print(c.most_common(1))
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counts = {}
names_list = ['John', 'Anne', 'Sam', 'Li', 'Sam', 'John']
for name in names_list:
counts[name] = counts.get(name,0) +1
print(counts)