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convert python to c++ online

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Mysterious Millipede answered on March 27, 2021 Popularity 1/10 Helpfulness 1/10

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convert python to c++ online

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# Execution of the Python Script
# - Save the python script with <Python_Script_Name>.py
# - Run the below command by giving the x1 y1 r1 ... values
# - The values are assumed to be Real/Integer constants
# python <Python_Script_Name>.py x1 y1 r1 x2 y2 r2 x3 y3 r3
# 
# If the command is not executed as provided above, the script
# would exit leaving "Check the input attributes" message.

import sys # Python Default sys module

if len(sys.argv) == 10:
    # Tower1 Inputs are casted to float values
    x1 = float(sys.argv[1])
    y1 = float(sys.argv[2])
    r1 = float(sys.argv[3])
    # Tower2 Inputs are casted to float values
    x2 = float(sys.argv[4])
    y2 = float(sys.argv[5])
    r2 = float(sys.argv[6])
    # Tower3 Inputs are casted to float values
    x3 = float(sys.argv[7])
    y3 = float(sys.argv[8])
    r3 = float(sys.argv[9])
else:
    print('Check the input attributes')
    exit(2)

# Printing the entered input values 
print('Input attributes for the three towers are : ')
print('Tower 1 attributes x1, y1, r1 : '),
print(x1, y1, r1)
print('Tower 2 attributes x2, y2, r2 : '),
print(x2, y2, r2)
print('Tower 3 attributes x3, y3, r3 : '),
print(x3, y3, r3)

# Calculating parameters based on the input values
A = (2 * x2) - (2 * x1)
B = (2 * y2) - (2 * y1)
C = r1 * 2 - r2 * 2 - x1 * 2 + x2 * 2 - y1 * 2 + y2 * 2
D = (2 * x3) - (2 * x2)
E = (2 * y3) - (2 * y2)
F = r2 * 2 - r3 * 2 - x2 * 2 + x3 * 2 - y2 * 2 + y3 * 2

# Calculate the device coordinates
Xcoordinate = ((C * E) - (F * B))/((E * A) - (B * D))
Ycoordinate = ((C * D) - (A * F))/((B * D) - (A * E))

# Printing the output values
print('Cell Phone Device X, Y coordinates are : '),
print(Xcoordinate, Ycoordinate)

# End of the file (EoF)

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Tags: c++ python

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Contributed on May 04 2021

Mysterious Millipede

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convert python to c++ online

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def create(n):
    l = []
    for i in range(1, n+1):
        l.append(i)
    return l
    
def operation(n ,p):
    l = []
    kl = []
    if p < n-1:
        return kl
    t = 0
    c = 1
    for i in range(n-1, 0, -1):
        c += 1
        if t+c+i-1 >= p:
            r = p-t-i+1
            l.append(r)
            for k in range(i-1):
                l.append(1)
            t = p
            break
        t += c
        l.append(c)
    if t < p:
        return k1
    return l
    
def operate(l ,ope):
    length = len(ope)
    for i in range(elngth):
        t = len(l) - (i+2)
        sp = t + ope[i]
        l = l[:t] + list(reversed(l[t:sp])) + l[sp:]
    return l

def main():
        inp = input().split()
        n = int(inp[0])
        p = int(inp[1])
        l = create(n)
        ope = operation(n, p)
        l = operate(l, ope)
        result = " "
        
        if ope:
            for item in l:
                result += str(item) + " "
            else
                result = "IMPOSSIBLE"
        print(f'Case # {str(i+1)} : {str(result)}')    

for i in range(int(input())):
    main()

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Contributed on Mar 27 2021

Dizzy Dunlin

0 Answers Avg Quality 2/10

convert c++ code to python online

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// Program to print path from root node to destination node
// for N*N -1 puzzle algorithm using Branch and Bound
// The solution assumes that instance of puzzle is solvable
#include <bits/stdc++.h>
using namespace std;
#define N 3

// state space tree nodes
struct Node
{
	// stores the parent node of the current node
	// helps in tracing path when the answer is found
	Node* parent;

	// stores matrix
	int mat[N][N];

	// stores blank tile coordinates
	int x, y;

	// stores the number of misplaced tiles
	int cost;

	// stores the number of moves so far
	int level;
};

// Function to print N x N matrix
int printMatrix(int mat[N][N])
{
	for (int i = 0; i < N; i++)
	{
		for (int j = 0; j < N; j++)
			printf("%d ", mat[i][j]);
		printf("\n");
	}
}

// Function to allocate a new node
Node* newNode(int mat[N][N], int x, int y, int newX,
			int newY, int level, Node* parent)
{
	Node* node = new Node;

	// set pointer for path to root
	node->parent = parent;

	// copy data from parent node to current node
	memcpy(node->mat, mat, sizeof node->mat);

	// move tile by 1 position
	swap(node->mat[x][y], node->mat[newX][newY]);

	// set number of misplaced tiles
	node->cost = INT_MAX;

	// set number of moves so far
	node->level = level;

	// update new blank tile cordinates
	node->x = newX;
	node->y = newY;

	return node;
}

// bottom, left, top, right
int row[] = { 1, 0, -1, 0 };
int col[] = { 0, -1, 0, 1 };

// Function to calculate the number of misplaced tiles
// ie. number of non-blank tiles not in their goal position
int calculateCost(int initial[N][N], int final[N][N])
{
	int count = 0;
	for (int i = 0; i < N; i++)
	for (int j = 0; j < N; j++)
		if (initial[i][j] && initial[i][j] != final[i][j])
		count++;
	return count;
}

// Function to check if (x, y) is a valid matrix cordinate
int isSafe(int x, int y)
{
	return (x >= 0 && x < N && y >= 0 && y < N);
}

// print path from root node to destination node
void printPath(Node* root)
{
	if (root == NULL)
		return;
	printPath(root->parent);
	printMatrix(root->mat);

	printf("\n");
}

// Comparison object to be used to order the heap
struct comp
{
	bool operator()(const Node* lhs, const Node* rhs) const
	{
		return (lhs->cost + lhs->level) > (rhs->cost + rhs->level);
	}
};

// Function to solve N*N - 1 puzzle algorithm using
// Branch and Bound. x and y are blank tile coordinates
// in initial state
void solve(int initial[N][N], int x, int y,
		int final[N][N])
{
	// Create a priority queue to store live nodes of
	// search tree;
	priority_queue<Node*, std::vector<Node*>, comp> pq;

	// create a root node and calculate its cost
	Node* root = newNode(initial, x, y, x, y, 0, NULL);
	root->cost = calculateCost(initial, final);

	// Add root to list of live nodes;
	pq.push(root);

	// Finds a live node with least cost,
	// add its childrens to list of live nodes and
	// finally deletes it from the list.
	while (!pq.empty())
	{
		// Find a live node with least estimated cost
		Node* min = pq.top();

		// The found node is deleted from the list of
		// live nodes
		pq.pop();

		// if min is an answer node
		if (min->cost == 0)
		{
			// print the path from root to destination;
			printPath(min);
			return;
		}

		// do for each child of min
		// max 4 children for a node
		for (int i = 0; i < 4; i++)
		{
			if (isSafe(min->x + row[i], min->y + col[i]))
			{
				// create a child node and calculate
				// its cost
				Node* child = newNode(min->mat, min->x,
							min->y, min->x + row[i],
							min->y + col[i],
							min->level + 1, min);
				child->cost = calculateCost(child->mat, final);

				// Add child to list of live nodes
				pq.push(child);
			}
		}
	}
}

// Driver code
int main()
{
	// Initial configuration
	// Value 0 is used for empty space
	int initial[N][N] =
	{
		{1, 2, 3},
		{5, 6, 0},
		{7, 8, 4}
	};

	// Solvable Final configuration
	// Value 0 is used for empty space
	int final[N][N] =
	{
		{1, 2, 3},
		{5, 8, 6},
		{0, 7, 4}
	};

	// Blank tile coordinates in initial
	// configuration
	int x = 1, y = 2;

	solve(initial, x, y, final);

	return 0;
}

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Tags: c++ python

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Contributed on Mar 30 2021

Fine Ferret

0 Answers Avg Quality 2/10

c++ to python converter online

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import torch
import torch.nn as nn
import torch.nn.functional as F


class BidirectionalLSTM(nn.Module):
    def __init__(self, n_in, n_hidden, n_out):
        super(BidirectionalLSTM, self).__init__()

        self.rnn = nn.LSTM(n_in, n_hidden, bidirectional=True)
        self.embedding = nn.Linear(n_hidden * 2, n_out)

    def forward(self, input):
        recurrent, _ = self.rnn(input)
        T, b, h = recurrent.size()
        t_rec = recurrent.view(T * b, h)

        output = self.embedding(t_rec)  # [T * b, nOut]
        output = output.view(T, b, -1)
        return output

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Contributed on Apr 01 2021

Friendly Fish

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c++ code to python code converter online

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#include<iostream>
#include<math.h>
#define vL 0.4
using namespace std;
struct generator
{
    float IL,theat,Pout;
};
typedef struct generator GENERATOR;
int main()
{
    int i=0,n;
    float sum=0,avg,low,high,il,theat;
    cout<<"Enter the value for 'n' : ";
    cin>>n;
    GENERATOR g[n];
    
    while(i<n)
    {
        cout<<"Enter Voltage and Current";
        cin>>il>>theat;
        if(il>0&&theat>=35&&theat<=45){
        g[i].IL=il;
        g[i].theat=theat;
        g[i].Pout=sqrt(3)*il*cos(theat);
        cout<<g[i].Pout;
        
        if(i==0)
        {
            low=g[i].Pout;
            high=g[i].Pout;
        }
        ++i;
        }else
            cout<<"\nEnter Valid data(il>0 and theat>=-35 and theat<=45)";
    }
    i=1;
    while(i<n)
    {
        if(low>g[i].Pout)
            low=g[i].Pout;
        if(high<g[i].Pout)
            high=g[i].Pout;
        sum+=g[i].Pout;
        i++;
    }
    avg=sum/n;
    cout<<"\nThe Lowest Output Power :"<<low;
    cout<<"\nThe highest Output Power :"<<high;
    cout<<"\nThe Average Output Power :"<<avg;
    
    
}
 OUTPUT

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Contributed on Apr 22 2021

Wide-eyed Wren

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c++ code to python code converter online

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void decrypt(string &text, string &key){
	for(size_t i=0;i<text.length()-1;i++){
		for (int j=0;j<26;j++){
			if (text[i]==key[j]){
				text[i]=j+97;
				break;
			}
		}
	}
}

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Contributed on Apr 26 2021

Nutty Nightingale

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convert c++ to python online

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#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;
void obradi(const vector<int>& particija, int k) {
  for (int i = 0; i < k; i++)
    cout << particija[i] << " ";
  cout << endl;
}
void obradiParticije(int n, int smax, vector<int>& particija, int k) {
  if (n <= 0)
    obradi(particija, k);
  else {
    for (int s = 1; s <= min(n, smax); s++) {
      particija[k] = s;
      obradiParticije(n-s, s, particija, k+1);
    }
}
void obradiParticije(int n) {
  vector<int> particija(n);
  obradiParticije(n, n, particija, 0);
}
int main() {
  int n;
  cin >> n;
  obradiParticije(n);

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Contributed on May 20 2021

Awful Albatross

0 Answers Avg Quality 2/10

c++ to python code converter

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#include<bits/stdc++.h>
#include <iostream>

using namespace std;


struct n{
    int d;
    struct n*next;
    };

void push(struct n**headref, int new_d)
{
    struct n* new_node=new n;
    new_node->d=new_d;
    new_node->next=(*headref);
    (*headref)=new_node;
    }
    
    float avgofnodes(struct n*head)
    {
        if(!head){return -1;}
        int c=0;
        int s=0;
        float avg =0.0;
        struct n*now=head;
        while(now!=NULL)
        {
            c++;
            s+=now->d;
            now=now->next;
            }
        avg=(double)s/c;
        return avg;
        }

int main()
{
struct n*head=NULL;
push(&head , 7);
push(&head, 6);
push(&head, 8);
push(&head, 4);
push(&head, 1);
	cout<<"Average of nodes = "<<avgofnodes(head);
return 0;	
}

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Contributed on May 20 2021

Crowded Civet

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c++ code to python code converter online

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#include<bits/stdc++.h>
#include <iostream>

using namespace std;


struct n{
    int d;
    struct n*next;
    };

void push(struct n**headref, int new_d)
{
    struct n* new_node=new n;
    new_node->d=new_d;
    new_node->next=(*headref);
    (*headref)=new_node;
    }
    
    float avgofnodes(struct n*head)
    {
        if(!head){return -1;}
        int c=0;
        int s=0;
        float avg =0.0;
        struct n*now=head;
        while(now!=NULL)
        {
            c++;
            s+=now->d;
            now=now->next;
            }
        avg=(double)s/c;
        return avg;
        }

int main()
{
struct n*head=NULL;
push(&head , 7);
push(&head, 6);
push(&head, 8);
push(&head, 4);
push(&head, 1);
	cout<<"Average of nodes = "<<avgofnodes(head);
return 0;	
}

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Contributed on May 21 2021

Crowded Civet

0 Answers Avg Quality 2/10

Free online converter of c ++ code to Python

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gfph
lp[kf
lb[plksp
gl[pl

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Contributed on May 23 2021

Mushy Mouse

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convert python to c++ online

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