Breaking News: Grepper is joining You.com. Read the official announcement!

pattern

Add Answer

sree_007 answered on May 22, 2021 Popularity 5/10 Helpfulness 1/10

answer pattern

related pattern

related patterns

pattern

Comment

rows = int(input("Enter the Number of rows: "))
cols = int(input("Enter the Number of cols: "))

for i in range(0, rows):
    for j in range(0, cols):
        if i == 0 or j == 0 or j == cols-1 or i == rows - 1:
            print("3", end="")
        else:
            print(i, end="")
    print()

# This code is contributed by Shubhanshu Arya (Prepinsta Placement Cell Student)

Popularity 5/10 Helpfulness 1/10 Language python

Source: prepinsta.com

Tags: python

Link to this answer
Share Copy Link

Contributed on May 22 2021

sree_007

0 Answers Avg Quality 2/10

Closely Related Answers

pattern

Comment

rows = int(input("Enter rows:"))
cols = int(input("Enter Cols:"))

for i in range(0, rows):
    for j in range(0, cols):
        if i==0 or j==0 or i == rows-1 or j == cols-1:
            print("*", end="")
        else:
            print(" ", end="")
    print()

# This code is contributed by Shubhanshu Arya (Prepinsta Placement Cell Student)

Popularity 6/10 Helpfulness 1/10 Language python

Source: prepinsta.com

Tags: python

Link to this answer
Share Copy Link

Contributed on May 22 2021

sree_007

0 Answers Avg Quality 2/10

pattern

Comment

num = int(input("Enter the Number: "))

for i in range(1, num+1):
    for j in range(0, num):
        print(i, end="")
    print()

# This code is contributed by Shubhanshu Arya (Prepinsta Placement Cell Student)

Popularity 4/10 Helpfulness 1/10 Language python

Source: prepinsta.com

Tags: python

Link to this answer
Share Copy Link

Contributed on May 22 2021

sree_007

0 Answers Avg Quality 2/10

pattern

Comment

num = int(input("Enter the Number: "))
k = 1
for i in range(0, num):
    for j in range(0, i+1):
        print(k, end="")
        k = k+1
    print()

# This code is contributed by Shubhanshu Arya (Prepinsta Placement Cell Student)

Popularity 4/10 Helpfulness 1/10 Language python

Source: prepinsta.com

Tags: python

Link to this answer
Share Copy Link

Contributed on May 22 2021

sree_007

0 Answers Avg Quality 2/10

pattern

Comment

        python
        
            
        
     import re
text, pattern = input(), input()
m= list(re.finditer("(?=(%s))"%pattern,text))
if not m:
    print((-1,-1))
for i in m:
    print((i.start(1),i.end(1)-1))

Popularity 3/10 Helpfulness 1/10 Language python

Source: www.thepoorcoder.com

Tags: python

Link to this answer
Share Copy Link

Contributed on Jun 29 2021

sree_007

0 Answers Avg Quality 2/10

patterns

Comment

    *
   #*#
  ##*##
 ###*###
 
 
 
 import java.util.Scanner;

public class Main {

	
	public static void main(String[] args) {
		
        
        Scanner sc= new Scanner(System.in);
        
        int n= sc.nextInt();
        
       for(int row=1;row<=n;row++)
       {
           for(int space=1;space<=n-row;rpw++)
           {
               System.out.print(" ");
           }
           
           for(int num=1;num<=row;num++)
           {
               System.out.print("*")
           }
       }

	}

}

Popularity 3/10 Helpfulness 1/10 Language java

Source: stackoverflow.com

Tags: java

Link to this answer
Share Copy Link

Contributed on Aug 24 2022

Aman Ahmed

0 Answers Avg Quality 2/10

pattern

Contents

More Related Answers

pattern

Closely Related Answers

pattern

pattern

pattern

pattern

patterns

Grepper

Documentation

Social

Legal

Contact

Oops, You will need to install Grepper and log-in to perform this action.