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pointers in c++

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Gifted Gull answered on July 15, 2021 Popularity 10/10 Helpfulness 1/10

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pointers in c++

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void simple_pointer_examples() {
    int   a;  // a can contain an integer
	int*  x;  // x can contain the memory address of an integer. 
 	char* y;  // y can contain the memory address of a char. 
 	Foo*  z;  // z can contain the memory address of a Foo object.  
 
    a = 10;
    x = &a;   // '&a' extracts address of a 
  
    std::cout <<  x << std::endl; // memory address of a => 0x7ffe9e25bffc
    std::cout << *x << std::endl; //          value of a => 10
}

Popularity 10/10 Helpfulness 1/10 Language cpp

Source: Grepper

Tags: c++ pointers

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Contributed on Jul 15 2021

Gifted Gull

0 Answers Avg Quality 2/10

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pointer c++

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int myvar = 6;
int pointer = &myvar; // adress of myvar
int value = *pointer; // the value the pointer points to: 6

Popularity 10/10 Helpfulness 3/10 Language cpp

Source: Grepper

Tags: c++

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Contributed on Sep 12 2021

FireTower

0 Answers Avg Quality 2/10

pointers in C++

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A pointer is a variable that points to a location in memory. Here is an example below:

#include <iostream>//For those unaware, the lib "iostream" stands for input output stream and is used mostly for stuff like cout or cin.
//int main() is the main function which will run upon running the exe file.
int main() {
	int x = 10;//The variable we are looking to point too
	int* xptr = &x;//using "&" you get the momory location of the variable x and you are telling xptr to point to x's location.
	std::cout<<xptr<<std::endl;//prints to location it's pointing too
	std::cout<<&x<<std::endl;//If you did it correctly it will output the same thing as xptr
	std::cout<<*xptr<<std::endl;//It will print the value(10) of the variable its pointing too. this is called derefrencing
	std::cout<<x;//It will print 10.
	return 0;
}

Popularity 10/10 Helpfulness 3/10 Language cpp

Source: Grepper

Tags: c++

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Contributed on Mar 20 2023

Wan Jun Yi

0 Answers Avg Quality 2/10

c++ pointer

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Pointers are datatypes that point to a value of another
variable using its memory adress. Pointers are declared as following:
int* pointer;

The value of pointers is the adress of the variable. When someone
wishes to adress the value behind the adress, he can do it like this:
*pointer = newValue;

The *-operator (dereference operator) can also be read
as "value pointed to by". The example above could in that way be
read as "Value pointed to by pointer is now newValue".
Note that the asterisk (*) used when declaring a pointer only
means that it is a pointer (it is part of its type compound pecifier),
and should not be confused with the dereference operator.
  
You can assign the adress of variables to pointers:
int foo1 = 24;
int* pointer = &foo1;

The &-operator (adress-of-operator) can be read as "adress-of".
Therefore the line with our pointer declaration can be read like
"int-pointer with name pointer has now the value of the adress of foo1"

Popularity 10/10 Helpfulness 3/10 Language cpp

Source: cplusplus.com

Tags: c++

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Contributed on Jun 28 2023

Distinct Deer

0 Answers Avg Quality 2/10

C/C++ Pointers

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int *p1;
int * p2;

Popularity 9/10 Helpfulness 3/10 Language c

Source: www.programiz.com

Tags: c pointers poi

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Contributed on Apr 17 2022

Friendly Fish

0 Answers Avg Quality 2/10

pointers in c++

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#include <iostream>

using namespace std;

int main()
{
   int x=5;
   int *ptr=&x;
   cout<<&x<<endl;        //prints the address of the variable (x)
   cout<<ptr<<endl;       //prints the address of the variable (x)
   cout<<*ptr<<endl;      //prints the value of x(5)
   cout<<&ptr<<endl;      //prints the address of the pointer (ptr)
   
   
}

Popularity 10/10 Helpfulness 3/10 Language cpp

Source: Grepper

Tags: c++

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Contributed on Jun 22 2022

S.Y

0 Answers Avg Quality 2/10

pointer cpp

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type *ptr;   // Declare a pointer variable called ptr as a pointer of type
// or
type* ptr;
// or
type * ptr;  // I shall adopt this convention

Popularity 9/10 Helpfulness 2/10 Language cpp

Source: www3.ntu.edu.sg

Tags: c++

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Contributed on Jul 26 2022

px4 firmware

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c++ pointers and functions

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#include <iostream>

using namespace std;

void increment(int *n){  		//declare argument of the functon as pointer
    *n+=1;
   cout<<"In function: "<<*n<<endl; 
}

int main()
{
   int x=5;			
   increment(&x);		//passing the address of the variable to the function
   cout<<"In main: "<<x<<endl;
   
}

Popularity 10/10 Helpfulness 2/10 Language cpp

Source: Grepper

Tags: c++

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Contributed on Jun 22 2022

S.Y

0 Answers Avg Quality 2/10

Pointers in c++

Comment

int x = 2;
int *y = &x;

cout << *y;

Popularity 10/10 Helpfulness 2/10 Language cpp

Source: Grepper

Tags: c++

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Contributed on Apr 18 2022

Msk SK

0 Answers Avg Quality 2/10

why do we use pointers in c++

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//why do we use pointers:
1)pass values by refrence to a function
2)return multiple values from a function
3)use pointers in combinational with arrays
4)dynamic memory allocation
5)use pointers in a base class in order to access object of derived class (Smart pointers)

Popularity 10/10 Helpfulness 2/10 Language cpp

Source: Grepper

Tags: c++

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Contributed on Jun 23 2022

S.Y

0 Answers Avg Quality 2/10

pointers in c++

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/*
Here is how pointers work in a nustshell(represent | as what's
happening in the memory and / as a place in the ram):
int x = 2; | 2/0x00ef5
int *z = &x| 0x00ef5/0x00ef6 (See how the value of the pointer z
matches with the memory address of x? that's how they work!)

when you print out the pointer as *n (replace n with the var name)
it will actually look at the value
see it's a memory address
go to that memory address
and print the value originally in the memory address which is 2

Here is code:
*/
int x = 5;
int *y = &x;
cout << *y+1;
/*
the reason why i did *y+1 was so to show that after it got
the value from the memory address it will add 1
*/

Popularity 10/10 Helpfulness 2/10 Language cpp

Source: Grepper

Tags: c++

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Contributed on Apr 18 2022

Msk SK

0 Answers Avg Quality 2/10

pointers in c++

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