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fibonacci

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Mero answered on January 1, 2021 Popularity 10/10 Helpfulness 1/10

answer fibonacci

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fibonacci

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f(n) = f(n-1) + f(n-2) 
                                  f(6)
                                   ^
  			                       /\
                f(5)               +                       f(4)
                ^
               /\                   +                        /\
                
        f(4)    +           f(3)                     f(3)    +    f(2)
       ^                       ^                     ^              ^
      /\                       /\                    /\            /\
   
 f(3)   +       f(2)            f(2) +f(1)       f(2) + f(1)   f(1) +  f(0)             
   ^              ^                ^                ^
   /\             /\                /\              /\
    
f(2) + f(1)      f(1) +  f(0)     f(1)+ f(0)       f(1) + f(0)         
  ^
  /\
f(1) +  f(0) 
  
//f(6) = 8   ==>  f(1)*8    f(1) appears 8 times 
 double feb  = (1/Math.pow(5,0.5)) * (Math.pow((1+Math.pow(5,0.5))/2,n)) - (1/Math.pow(5,0.5))* (Math.pow((1-Math.pow(5,0.5))/2,n));  
  
f(1) == 1;

Popularity 10/10 Helpfulness 1/10 Language java

Source: Grepper

Tags: fibonacci java

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Contributed on Aug 01 2021

Mero

0 Answers Avg Quality 2/10

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fibbonacci

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0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377, 610, 987, 1597, 2584, 4181, 6765, 10946, 17711, 28657, 46368, 75025, 121393, 196418, 317811,

Popularity 10/10 Helpfulness 4/10 Language whatever

Source: google.com

Tags: whatever whateve

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Contributed on Feb 01 2021

Joyous Jaguar

0 Answers Avg Quality 2/10

fibonacci

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# Easy fibonacci exercise
# Method #1
def fibonacci(n):
    # 1th: 0
    # 2th: 1
    # 3th: 1 ...
    if n == 1:
        return 0
    elif n == 2:
        return 1
    else:
        return fibonacci(n - 1) + fibonacci(n - 2)

# Method #2
def fibonacci2(n):
    if n == 0: return 0
    n1 = 1
    n2 = 1
    # (1, n - 2) because start by 1, 2, 3... not 0, 1, 1, 2, 3....
    for i in range(1, n - 2):
        n1 += n2
        n2 = n1 - n2
    return n1


print(fibonacci(13))
# return the nth element in the fibonacci sequence

Popularity 10/10 Helpfulness 4/10 Language python

Source: Grepper

Tags: fibonacci fibo

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Contributed on Jan 01 2021

Solo developer

0 Answers Avg Quality 2/10

fibonacci

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def fibonacci(n):
    if n == 0:
        return 0
    elif n == 1:
        return 1
    return fibonacci(n - 1) + fibonacci(n - 2)

Popularity 10/10 Helpfulness 3/10 Language whatever

Source: dbader.org

Tags: fibonacci fibo

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Contributed on Oct 16 2021

Shy Shrike

0 Answers Avg Quality 2/10

fibonacci

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def fibonacci(n):
    if n <= 1:
        return n
    else:
        return fibonacci(n-1) + fibonacci(n-2)

limit = int(input("Insert the number of the values of the series that you would see: "))

for num in range(1, limit+1):
    print(fibonacci(num))

Popularity 10/10 Helpfulness 2/10 Language python

Source: www.programmareinpython.it

Tags: fibonacci fibo

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Contributed on Dec 01 2021

Obnoxious Opossum

0 Answers Avg Quality 2/10

Fibonacci , fibo

Comment

function fib(n) {  if (n < 2){    return n  }  return fib(n - 1) + fib (n - 2)}

Popularity 10/10 Helpfulness 2/10 Language javascript

Source: medium.com

Tags: fibonacci fibo

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Contributed on Sep 11 2021

Clever Cheetah

0 Answers Avg Quality 2/10

fibonacci

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#include <iostream>

using namespace std;

int fibonacci(int n) {
    int fib1 = 0;  // fib(1)
    int fib2 = 1;  // fib(2)
    int fib = 0;   // To store the Fibonacci number

    for (int i = 3; i <= n; ++i) {
        fib = fib1 + fib2;
        fib1 = fib2;
        fib2 = fib;
    }

    return fib;
}

int main() {
    int n;
    cin >> n;  // Read the input

    // Calculate and print the Fibonacci number of N
    cout << fibonacci(n) << endl;

    return 0;
}

Popularity 9/10 Helpfulness 2/10 Language cpp

Source: chat.openai.com

Tags: c++

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Contributed on Jun 22 2023

red-kid

0 Answers Avg Quality 2/10

Fibonacci

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# Fibonacci in Python

# Functional programming
from functools import reduce
 
fib1 = lambda n: reduce(lambda x, _: x+[x[-1]+x[-2]],
                                 range(n-2), [0, 1])
 
print(fib1(5))

# Iterative
def Fibonacci(n):
    f0, f1 = 0, 1
    for _ in range(n):
        yield f0
        f0, f1 = f1, f0+f1

fib2 = list(Fibonacci(5))
print(fib2)

Popularity 9/10 Helpfulness 1/10 Language python

Source: Grepper

Tags: fibonacci fibo

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Contributed on May 17 2023

Mackerel

0 Answers Avg Quality 2/10

Fibonacci

Comment

fib=lambda x: x if x<=1 else fib(x-1) + fib(x-2)

Popularity 10/10 Helpfulness 1/10 Language python

Source: dev.to

Tags: fibonacci fibo

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Contributed on Sep 30 2022

David K.

0 Answers Avg Quality 2/10

Fibonacci

Comment

public static long Fibonacci(long n) {
    if (n <= 1) {
        return n;
    }

    long a = 0;
    long b = 1;
    long c = 0;

    if (n >= 2) {
        a = Fibonacci(n - 1); // Recursive call to calculate Fibonacci(n-1)
        b = Fibonacci(n - 2); // Recursive call to calculate Fibonacci(n-2)
        c = a + b; // Calculate the current Fibonacci number
    }

    return c;
}

Popularity 9/10 Helpfulness 1/10 Language css

Source: chat.openai.com

Tags: css fibonacci fi

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Contributed on Jun 16 2023

Abdul Aziz

0 Answers Avg Quality 2/10

fibonacci

Comment

import gmpy2
from gmpy2 import mpz

def gmp_fib(n):
    a, b = power(mpz(1), mpz(0), mpz(n))
    return a

Popularity 9/10 Helpfulness 1/10 Language whatever

Source: www.oranlooney.com

Tags: fibonacci fibo

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Contributed on Jan 22 2024

Steve T

0 Answers Avg Quality 2/10

fibonacci

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