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Tower of Hanoi

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Itchy Impala answered on April 4, 2021 Popularity 8/10 Helpfulness 3/10

answer Tower of Hanoi

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Tower of Hanoi

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def towerOfHanoi(N , source, destination, auxiliary):
	if N==1:
		print("Move disk 1 from source",source,"to destination",destination)
		return
	towerOfHanoi(N-1, source, auxiliary, destination)
	print("Move disk",N,"from source",source,"to destination",destination)
	towerOfHanoi(N-1, auxiliary, destination, source)
		
# Driver code
N = 3
towerOfHanoi(N,'A','B','C')
# A, C, B are the name of rods

Popularity 8/10 Helpfulness 3/10 Language python

Source: favtutor.com

Tags: python

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Contributed on Aug 12 2021

Itchy Impala

0 Answers Avg Quality 2/10

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Tower of Hanoi

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def tower_of_hanoi(n, source, destination, auxiliary):
    if n > 0:
        tower_of_hanoi(n-1, source, auxiliary, destination)
        print(f"Move disk {n} from {source} to {destination}")
        tower_of_hanoi(n-1, auxiliary, destination, source)

# Example usage: solving Tower of Hanoi for 3 disks
tower_of_hanoi(3, 'A', 'C', 'B')

Popularity 5/10 Helpfulness 2/10 Language python

Source: chat.openai.com

Tags: whatever

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Contributed on Jun 18 2023

FLOID

0 Answers Avg Quality 2/10

tower of hanoi

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// C++ recursive function to
// solve tower of hanoi puzzle
#include <bits/stdc++.h>
using namespace std;
 
void towerOfHanoi(int n, char from_rod, char to_rod,
                  char aux_rod)
{
    if (n == 0) {
        return;
    }
    towerOfHanoi(n - 1, from_rod, aux_rod, to_rod);
    cout << "Move disk " << n << " from rod " << from_rod
         << " to rod " << to_rod << endl;
    towerOfHanoi(n - 1, aux_rod, to_rod, from_rod);
}
 
// Driver code
int main()
{
    int N = 3;
 
    // A, B and C are names of rods
    towerOfHanoi(N, 'A', 'C', 'B');
    return 0;
}
 
// This is code is contributed by rathbhupendra

Popularity 7/10 Helpfulness 2/10 Language cpp

Source: www.geeksforgeeks.org

Tags: c++

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Contributed on Oct 21 2022

Araf

0 Answers Avg Quality 2/10

tower of hanoi

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/// find total number of steps 
int towerOfHanoi(int n) {
  /// pow(2,n)-1
  if (n == 0) return 0;
  
  return towerOfHanoi(n - 1) + 1 + towerOfHanoi(n - 1);
}

Popularity 9/10 Helpfulness 2/10 Language cpp

Source: Grepper

Tags: c++

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Contributed on Apr 04 2021

paramjeetdhiman

0 Answers Avg Quality 2/10

tower of hanoi

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# Recursive Python function to solve tower of hanoi
 
def TowerOfHanoi(n , from_rod, to_rod, aux_rod):
    if n == 0:
        return
    TowerOfHanoi(n-1, from_rod, aux_rod, to_rod)
    print("Move disk",n,"from rod",from_rod,"to rod",to_rod)
    TowerOfHanoi(n-1, aux_rod, to_rod, from_rod)
         
# Driver code
n = 4
TowerOfHanoi(n, 'A', 'C', 'B')
# A, C, B are the name of rods
 
# Contributed By Harshit Agrawal

Popularity 8/10 Helpfulness 1/10 Language whatever

Source: www.geeksforgeeks.org

Tags: whatever whateve

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Contributed on Feb 16 2022

Magnificent Mink

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tower of hanoi

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#include <iostream>
#include <math.h>
struct Node{    
    int diam;
    Node* next;}; 
class Stack
{
private:
    Node* top;
public:
    Stack();
    bool push(int);
    int pop();
    int peek();
    int count();
    void print();
    bool isEmpty();
}; 
Stack::Stack(){
    top = NULL;
} 
bool Stack::push(int diam){
    bool status = false;    
    Node* temp = new Node();
    temp->diam = diam;
    temp->next = top;
    top = temp;
    if(top->diam == diam){
        status = true;
    }
    return status;
}
bool Stack::isEmpty(){
    bool status = false;
    if(top == NULL){
        status = true;
    }
    return status;
} 
int Stack::pop(){
    int value = INT_MIN;
    if(top){
        Node* temp = top;
        value = temp->diam;
        top = temp->next;
        delete(temp);
    }
    return value;
} 
int Stack::count(){
    int count = 0;
    Node* temp = top;
    while(temp){
        count++;
        temp = temp->next;
    }
    return count;
} 
int Stack::peek(){
    int value = INT_MIN;
    if(top){
        value = top->diam;
    }
    return value;
} 
void Stack::print(){
    Node* temp = top;
    while(temp){
        std::cout << temp->diam << ' ';
        temp = temp->next;
    }
} 
void moveDisk(Stack *source, Stack *destination){
    int tower1Top = source->pop();
    int tower2Top = destination->pop();
        if(tower1Top == INT_MIN){
        source->push(tower2Top);
    }
    else if(tower2Top ==INT_MIN){
        destination->push(tower1Top);
    }
    else if(tower1Top > tower2Top){
        source->push(tower1Top);
        source->push(tower2Top);
    }
    else{
        destination->push(tower2Top);
        destination->push(tower1Top);
    }
}
int main() {
    Stack towerOne;
    Stack towerTwo;
    Stack towerThree;
    int towerSize = 10;
    if(towerOne.isEmpty() && towerTwo.isEmpty() && towerThree.isEmpty()){
        std::cout << "Three empty stacks created" << std::endl;
    }
    std::cout << '\n';
    std::cout << "Putting " << towerSize << " plates of subsequently smaller diameter on towerOne" << std::endl;
    for(int i=towerSize; i>0; i--){
        towerOne.push(i);
    }
    std::cout << '\n';
    
    std::cout << "Printing Tower One: " << std::endl;
    towerOne.print();
    std::cout << '\n';
    std::cout << '\n';
    std::cout << "Testing pop() on Tower One (removing top value):" << std::endl;
    std::cout << towerOne.pop() << std::endl;
    std::cout << "Tower Size is now " << towerSize-1 << std::endl;
    std::cout << '\n';
    std::cout << "Printing updated list:" << std::endl;
    towerOne.print();
    std::cout << '\n';
    std::cout << '\n';
    std::cout << "Testing peek()" << std::endl;
    std::cout << towerOne.peek() << std::endl;
    std::cout << '\n';
    std::cout << "Testing count()" << std::endl;
    std::cout << towerOne.count() << std::endl;
    std::cout << '\n';
    
    int total_moves = pow(2, towerOne.count()) - 1;
    std::cout << "Running Towers of Hanoi algorithm" << std::endl;
    if(towerOne.count()%2 != 0){
        for(int i=1; i<=total_moves; i++){
            if(i%3==1){
                moveDisk(&towerOne, &towerThree);
            }
            else if(i%3==2){
                moveDisk(&towerOne, &towerTwo);
            }
            else if(i%3==0){
                moveDisk(&towerTwo, &towerThree);
            }
        }
    }
    else if(towerOne.count()%2==0){
        for(int i=1; i<=total_moves; i++){
            if(i%3==1){
                moveDisk(&towerOne, &towerTwo);
            }
            else if(i%3==2){
                moveDisk(&towerOne, &towerThree);
            }
            else if(i%3==0){
                moveDisk(&towerTwo, &towerThree);
            }
        }
    }
    std::cout << "Checking Tower Three count is equal to " << towerSize-1 << std::endl;
    std::cout << "Tower Three Count: " << towerThree.count() << std::endl;
    std::cout << "\n";
    std::cout << "Checking Tower Three elements are in ascending order " << std::endl;
    towerThree.print();
    std::cout << "\n";
 }

Popularity 7/10 Helpfulness 1/10 Language whatever

Source: alecgarza96.medium.com

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Contributed on Oct 18 2022

Muhammad Umar Javid

0 Answers Avg Quality 2/10

Tower of Hanoi Algorithm

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#include <stdio.h>

void tower_of_hanoi(int n, char source, char destination, char auxiliary) {
    if (n > 0) {
        tower_of_hanoi(n-1, source, auxiliary, destination);
        printf("Move disk %d from %c to %c\n", n, source, destination);
        tower_of_hanoi(n-1, auxiliary, destination, source);
    }
}

int main() {
    int n = 3;  // Number of disks
    char source = 'A';
    char destination = 'C';
    char auxiliary = 'B';

    tower_of_hanoi(n, source, destination, auxiliary);

    return 0;
}

Popularity 7/10 Helpfulness 1/10 Language python

Source: chat.openai.com

Tags: python algorithm pyth

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Contributed on Jun 18 2023

FLOID

0 Answers Avg Quality 2/10

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