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StringIndexer pyspark

Sore Stork answered on September 19, 2021 Popularity 8/10 Helpfulness 1/10

answer StringIndexer pyspark

StringIndexer pyspark

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-1

df_i = spark.createDataFrame([
    ("a", 2.0),
    ("c", 1.0),
    ("b", 2.0),    
    ("a", 1.0),
    ("a", 0.0),   
    ("c", 1.0)
], ["categoryIndex", "categoryIndex2"])
stringID = StringIndexer(inputCol="categoryIndex",outputCol="categoryIndex2")
indexer = stringID.fit(df_i)
df_i = indexer.transform(df_i)
df_i.show()

Popularity 8/10 Helpfulness 1/10 Language python

Source: Grepper

Tags: pyspark python

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Contributed on Sep 19 2021

Sore Stork

0 Answers Avg Quality 2/10

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