Breaking News: Grepper is joining You.com. Read the official announcement!

return@

Add Answer

Ugly Unicorn answered on October 9, 2021 Popularity 9/10 Helpfulness 2/10

answer return@

related return

related return@

return@

Comment

fun foo(ints: List<Int>): List<String> {
    val result = ints.map f@{
        if (it == 0) return@f "zero" // return at named label
        if (it == -1) return emptyList() // return at foo
        "number $it" // expression returned from lambda
    }
    return result
}

foo(listOf(1, -1, 1)) // []
foo(listOf(1, 0, 1)) // ["number 1", "zero", "number 1"]

Popularity 9/10 Helpfulness 2/10 Language whatever

Source: stackoverflow.com

Tags: whatever

Link to this answer
Share Copy Link

Contributed on Oct 09 2021

Ugly Unicorn

0 Answers Avg Quality 2/10

Closely Related Answers

return

Comment

if return is confusing like it was for me let me tell you
how it became easy for me.
see this
function Name()
return "Ali"
end

local name = Name()
print(name)
--it should print Ali
that how return in lua works you Call a function as a Veriable
that Veriable will Catch the return know that in lua functions
yield a thread that means line 8 will yield until the Name() function has
finished executing thats what i call that function dead / we cant
resume it anymore. i dont wanna get into coroutines just know a thread /
function is dead when arriving to end / return or an error line.

Popularity 10/10 Helpfulness 3/10 Language whatever

Source: Grepper

Tags: return re

Link to this answer
Share Copy Link

Contributed on May 26 2022

Botter3029

0 Answers Avg Quality 2/10

return

Comment

function timesFive(num) {
  return num * 5;
}
const answer = timesFive(9)
console.log(answer)

Popularity 8/10 Helpfulness 2/10 Language javascript

Source: Grepper

Tags: javascript j

Link to this answer
Share Copy Link

Contributed on Feb 13 2023

Thoughtless Turkey

0 Answers Avg Quality 2/10

return

Comment

function App() {
 let [name, setName] = useState("Ned stark");
 // we declare the input inside the variable
 let nameRef = useRef();
 // we are referring to input to change the value
 const submitButton = () => {
   setName(nameRef.current.value);
 };

 return (
   <div className="App">
     <p>{name}</p>
     <h1>Who is your favorite Games of throne character</h1>

     <div>
       <input
         placehoder="enter your preferred GOT character..."
         ref={nameRef}
         type="text"
       />
       <button type="button" onClick={submitButton}>
         Submit
       </button>
     </div>
   </div>
 );
}

Popularity 9/10 Helpfulness 1/10 Language javascript

Source: learn.gomycode.co

Tags: javascript j

Link to this answer
Share Copy Link

Contributed on Jan 25 2022

Attractive Alligator

0 Answers Avg Quality 2/10

return@

Comment

fun foo(ints: List<Int>) {
    ints.forEach {
        if (it == 0) return@forEach // implicit label for lambda passed to forEach
        print(it)
    }
}

Popularity 9/10 Helpfulness 1/10 Language whatever

Source: stackoverflow.com

Tags: whatever whateve

Link to this answer
Share Copy Link

Contributed on Oct 09 2021

Ugly Unicorn

0 Answers Avg Quality 2/10

return@

Contents

More Related Answers

return@

Closely Related Answers

return

return

return

return@

Grepper

Documentation

Social

Legal

Contact

Oops, You will need to install Grepper and log-in to perform this action.