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diamond shape in python

Fawlid answered on November 6, 2021 Popularity 7/10 Helpfulness 3/10

answer diamond shape in python

related python code for create diamond shape with integer

diamond shape in python

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def p(n):
    for i in range(n):
        print(" "*(n-i-1),end="")
        print("* "*(i+1))
        
    for j in range(n-1, 0, -1):
        print(" "*(n-j),end="")
        print("* "*(j))

star_num = int(input("Enter a number that shows diameters of your diamond shape: "))
print(p(star_num))

Popularity 7/10 Helpfulness 3/10 Language python

Source: Grepper

Tags: python

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Contributed on Nov 06 2021

Fawlid

0 Answers Avg Quality 2/10

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python code for create diamond shape with integer

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n = 9
print("Pattern 1")
for a1 in range(1, (n+1)//2 + 1): #from row 1 to 5
    for a2 in range((n+1)//2 - a1):
        print(" ", end = "")
    for a3 in range((a1*2)-1):
        print("*", end = "")
    print()

for a1 in range((n+1)//2 + 1, n + 1): #from row 6 to 9
    for a2 in range(a1 - (n+1)//2):
        print(" ", end = "")
    for a3 in range((n+1 - a1)*2 - 1):
        print("*", end = "")
    print()

Popularity 6/10 Helpfulness 3/10 Language python

Source: stackoverflow.com

Tags: integer python

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Contributed on Dec 02 2021

Exuberant Emu

0 Answers Avg Quality 2/10

diamond shape in python

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diamond shape in python

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python code for create diamond shape with integer

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