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python sorted lambda

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JessiCoder answered on March 22, 2021 Popularity 10/10 Helpfulness 5/10

answer python sorted lambda

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python sorted lambda

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a = ["tim", "bob", "anna", "steve", "john"]

# sorts the list by the first letter of each name
b = sorted(a, key=lambda x : x[0])
# x = each of the values in the list a

# sorts the list by length FIRST, then alphabetical order SECOND
c = sorted(a, key=lambda x : (len(x), x))

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Contributed on Nov 10 2021

JessiCoder

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python sort based off lambda

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a = sorted(a, key=lambda x: x.modified, reverse=True)

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Contributed on Mar 22 2021

Hilarious Hawk

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sort() with lambda

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lst = ['id01', 'id10', 'id02', 'id12', 'id03', 'id13']
lst_sorted = sorted(lst, key=lambda x: int(x[2:]))
print(lst_sorted)

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Source: www.delftstack.com

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Contributed on Aug 05 2022

VVinayaka

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sorted lambda

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sorted(student_tuples, key=lambda student: student[2])

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Contributed on Apr 21 2021

Serhii

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python sorted lambda

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