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bash sed with variable

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Shy Shrew answered on July 7, 2020 Popularity 9/10 Helpfulness 4/10

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bash sed with variable

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# If you want to store your regex in a bash variable 
# and use it in sed, you might need the following
BASE_REGEX="[0-9]{4}\.[0-9]+"
REGEX_ESCAPED=$(sed 's/[}{)(+]/\\&/g; s/\^/\\^/g' <<< "$BASE_REGEX")

# One variable can be used with sed
sed -i "s/${REGEX_ESCAPED}/REPLACEMENT/g" file.txt
# The other can be used with bash internal regex operator
if [[ "2022.42" =~ ^${BASE_REGEX}$ ]]
then
	echo 'Matches !'
fi

Popularity 9/10 Helpfulness 4/10 Language shell

Source: Grepper

Tags: bash sed shell

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Contributed on Nov 23 2021

Shy Shrew

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sed with variables in shell script

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Use double quotes for the sed expression.

sed "s/$replace_string/$replace_with/"`

Popularity 9/10 Helpfulness 2/10 Language shell

Source: Grepper

Tags: script sc

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Contributed on Jul 07 2020

Devops Captain

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passing bash variable to sed

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rr=abcd # in shell

sed -i "s/aaa/$rr/g" file.dat 

# -i will update thefile,

Popularity 8/10 Helpfulness 1/10 Language shell

Source: unix.stackexchange.com

Tags: bash command c

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Contributed on May 26 2021

Niransha

0 Answers Avg Quality 2/10

sed with variable

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Using double quotes
Use double quotes to make the shell expand variables while preserving whitespace:

sed -i "s/$var1/ZZ/g" "$file"
When you require the quote character in the replacement string, you have to precede it with a backslash which will be interpreted by the shell. In the following example, the string quote me will be replaced by "quote me" (the character & is interpreted by sed):

sed -i "s/quote me/\"&\"/" "$file"
Using single quotes
If you've a lot shell meta-characters, consider using single quotes for the pattern, and double quotes for the variable:

sed -i 's,'"$pattern"',Say hurrah to &: \0/,' "$file"

Popularity 7/10 Helpfulness 1/10 Language shell

Source: askubuntu.com

Tags: sed shell

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Contributed on Aug 21 2023

DreamCoder

0 Answers Avg Quality 2/10

bash sed with variable

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