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import pandas
pandas.date_range(sdate,edate-timedelta(days=1),freq='d')
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# python 3.x
import datetime
import pandas as pd
start = datetime.datetime.strptime("01-12-2021", "%d-%m-%Y")
end = datetime.datetime.strptime("07-12-2021", "%d-%m-%Y")
date_generated = pd.date_range(start, end)
print date_generated.strftime("%d-%m-%Y")
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from datetime import datetime, timedelta
def date_range(start, end):
delta = end - start # as timedelta
days = [start + timedelta(days=i) for i in range(delta.days + 1)]
return days
start_date = datetime(2008, 8, 1)
end_date = datetime(2008, 8, 3)
print(date_range(start_date, end_date))
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# Timedelta function demonstration
from datetime import datetime, timedelta
# Using current time
time_for_now = datetime.now()
# printing initial_date
print("initial_date", str(time_for_now))
# Some another datetime
new_final_time = time_for_now + \
timedelta(days=2)
# printing new final_date
print("new_final_time", str(new_final_time))
# printing calculated past_dates
print('Time difference:', str(new_final_time - time_for_now))
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# If you convert all your date to `datetime.date`, you can write the following:
if start <= date <= end:
print("in between")
else:
print("No!")