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# any list
a = [1, 7, 3, 12, 5]
# index of minimum element
# if more than 1 minimum,
# first index is returned
min_index = a.index(min(a))
# index of maximum element
max_index = a.index(max(a))
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numbers = [5, 4, 7, 3, 9, 1, 2]
biggest_number = max(numbers)
print(numbers.index(biggest_number))
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import numpy
input_list = [15,20,35,42,12,8]
max_value = numpy.argmax(input_list)
print(max_value)
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mylist = [1, 7, 3, 12, 5]
min_value = min(mylist)
max_value = max(mylist)
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number_list = [1, 2, 3]
max_value = max(number_list)
# Return the max value of the list
max_index = number_list.index(max_value)
# Find the index of the max value
print(max_index)
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def Max_min(list_of_number):
largest_number = 0
for num in list_of_number:
if num > largest_number:
largest_number = num
return largest_number
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>>> m = max(a)
>>> [i for i, j in enumerate(a) if j == m]
[9, 12]