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Check status code urllib

Jolly Jackal answered on January 15, 2022 Popularity 7/10 Helpfulness 4/10

answer Check status code urllib

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Check status code urllib

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import urllib.request, urllib.error

url = 'http://www.google.com/asdfsf'
try:
    conn = urllib.request.urlopen(url)
except urllib.error.HTTPError as e:
    # Return code error (e.g. 404, 501, ...)
    # ...
    print('HTTPError: {}'.format(e.code))
except urllib.error.URLError as e:
    # Not an HTTP-specific error (e.g. connection refused)
    # ...
    print('URLError: {}'.format(e.reason))
else:
    # 200
    # ...
    print('good')

Popularity 7/10 Helpfulness 4/10 Language python

Source: stackoverflow.com

Tags: python status urllib

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Contributed on Jan 15 2022

Jolly Jackal

0 Answers Avg Quality 2/10

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Check status code urllib

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import urllib2

req = urllib2.Request('http://www.python.org/fish.html')
try:
    resp = urllib2.urlopen(req)
except urllib2.HTTPError as e:
    if e.code == 404:
        # do something...
    else:
        # ...
except urllib2.URLError as e:
    # Not an HTTP-specific error (e.g. connection refused)
    # ...
else:
    # 200
    body = resp.read()

Popularity 7/10 Helpfulness 4/10 Language python

Source: stackoverflow.com

Tags: status urllib python ur

Link to this answer
Share Copy Link

Contributed on Jan 15 2022

Jolly Jackal

0 Answers Avg Quality 2/10

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Check status code urllib

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