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binary tree level traversal

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PrashantUnity answered on January 16, 2022 Popularity 10/10 Helpfulness 2/10

answer binary tree level traversal

related binary tree level order traversal

related level order traversal of binary tree c++

binary tree level traversal

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    public static void levelOrderTraversal(Node root)
    {
        // base case
        if (root == null) {
            return;
        }
 
        // create an empty queue and enqueue the root node
        Queue<Node> queue = new ArrayDeque<>();
        queue.add(root);
 
        // to store the current node
        Node curr;
 
        // loop till queue is empty
        while (!queue.isEmpty())
        {
            // process each node in the queue and enqueue their
            // non-empty left and right child
            curr = queue.poll();
 
            System.out.print(curr.key + " ");
 
            if (curr.left != null) {
                queue.add(curr.left);
            }
 
            if (curr.right != null) {
                queue.add(curr.right);
            }
        }
    }

Popularity 10/10 Helpfulness 2/10 Language java

Source: www.techiedelight.com

Tags: binary-tree java traversal

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Contributed on Jan 16 2022

PrashantUnity

0 Answers Avg Quality 2/10

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binary tree level order traversal

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/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode() {}
 *     TreeNode(int val) { this.val = val; }
 *     TreeNode(int val, TreeNode left, TreeNode right) {
 *         this.val = val;
 *         this.left = left;
 *         this.right = right;
 *     }
 * }
 */
class Solution {
    public List<List<Integer>> levelOrder(TreeNode root) {
        List<List<Integer>> list = new ArrayList<>();
        Deque<TreeNode> queue = new ArrayDeque<>();
        if(root==null)
            return list;
        queue.offerLast(root);
        while(!queue.isEmpty())
        {
            ArrayList<Integer> l= new ArrayList<>();
            int size=queue.size();
            for(int i=0;i<size;i++)
            {
                TreeNode node=queue.pollFirst();
                if(node.left!=null)
                    queue.offerLast(node.left);
                if(node.right!=null)
                    queue.offerLast(node.right);
                l.add(node.val);

            }
            list.add(l);

        }

        return list;
        
        
    }
}

Popularity 9/10 Helpfulness 1/10 Language java

Source: Grepper

Tags: binary-tree bina

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Contributed on Jun 22 2023

Zealous Zebra

0 Answers Avg Quality 2/10

level order traversal of binary tree c++

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/*
node class contains:
node* left;
node* right;
int value;
*/
void levelOrder(node* root){
  node* ptr=nullptr;
  queue<node*> q;
  q.push(root);
  while(!q.empty()){
    ptr=q.front();
    cout<<ptr->value<<endl;
    if(ptr->left!=nullptr){
q.push(ptr->left);
  }
    if(ptr->right!=nullptr){
    q.push(ptr->right);
    }
    q.pop();
  }
}

Popularity 10/10 Helpfulness 1/10 Language cpp

Source: Grepper

Tags: binary-tree bina

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Contributed on May 01 2022

Shiny Spider

0 Answers Avg Quality 2/10

binary tree level traversal

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binary tree level traversal

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binary tree level order traversal

level order traversal of binary tree c++

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