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numpy.where() for substring

Tirbo06 answered on January 18, 2022 Popularity 1/10 Helpfulness 1/10

answer numpy.where() for substring

numpy.where() for substring

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foo = 'aa'
bar = np.array(['aaa', 'aab', 'aca'])
out = [i for i, v in enumerate(bar) if foo in v]
# out = [0, 1]

bar = ['aca', 'bba', 'baa', 'aaf', 'ccc']
out = [i for i, v in enumerate(bar) if foo in v]
# out = [2, 3]

Popularity 1/10 Helpfulness 1/10 Language python

Source: stackoverflow.com

Tags: python substring

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Contributed on Jan 18 2022

Tirbo06

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numpy.where() for substring

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