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binary add using strings

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Sleep deprived answered on January 26, 2022 Popularity 8/10 Helpfulness 1/10

answer binary add using strings

related binary string addition

related add binary strings

binary add using strings

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-1

#include <iostream>
#include <string>
using namespace std;

int DecToBin(int dec)
{
    long long bin = 0;
    int j,rem, i = 1;

    for(j=dec;j!=0;j)
    {
        rem = j % 2;
        j /= 2;
        bin += rem * i;
        i *= 10;
    }

    return bin;
}

int main()
{
    string number_1, number_2;
    int decimal_sum;

    cout<< "Enter first number: ";
    cin>> number_1;

    cout<< "Enter second number: ";
    cin>> number_2;

    decimal_sum = stoi(number_1 , 0 ,2) + stoi(number_2 , 0 ,2);

    cout<< "Binary Sum = " <<DecToBin(decimal_sum);

    return 0;
}

Popularity 8/10 Helpfulness 1/10 Language cpp

Source: Grepper

Tags: add binary c++ using

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Contributed on Jan 26 2022

Sleep deprived

0 Answers Avg Quality 2/10

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binary string addition

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//** fastest solution possible **//
#include <string_view>
#define int int_least8_t
class Solution {
public:
    string addBinary(const string_view& a, const string_view& b) {
        bool carry = 0;
        const string_view* small;
        const string_view* large;
        if(a.size() > b.size()) {
            small = &b;
            large = &a;
        }
        else {
            small = &a;
            large = &b;
        }
        
        string ans;
      	ans.reserve (a.size());
        int itrL = large[0].size() - 1;
        for(int i = small[0].size() - 1; i >= 0; i--) {
            if(small[0][i] == '1' && large[0][itrL] == '1' && carry == 1) {
                ans += "1";
                carry = 1;
            }
            else if(small[0][i] == '1' && large[0][itrL] == '1' && carry == 0) {
                ans += "0";
                carry = 1;
            }
            else if((small[0][i] == '1' && large[0][itrL] == '0' && carry == 0) 
                 || (small[0][i] == '0' && large[0][itrL] == '1' && carry == 0) ) {
                ans += "1";
                carry = 0;
            }
            else if(small[0][i] == '0' && large[0][itrL] == '0' && carry == 1){
                ans += "1";
                carry = 0;
            }
            else if(small[0][i] == '0' && large[0][itrL] == '0' && carry == 0){
                ans += "0";
                carry = 0;
            }
            else {
                ans += "0";
                carry = 1;
            }
            itrL--;
        }
        
        while(itrL >= 0){
             if(large[0][itrL] == '1' && carry == 1){
                ans+="0";
                carry=1;
            }
            else if((large[0][itrL] == '1' && carry == 0)
                 || (large[0][itrL] == '0' && carry == 1)){
                ans += "1";
                carry = 0;
            }
            else{
                ans += "0";
                carry = 0;
            }
            itrL--;
        }
        
        if(carry == 1){
            ans += "1";
        }
        
        reverse(ans.begin(), ans.end());
        return ans;
    }
};
#undef int

Popularity 6/10 Helpfulness 5/10 Language cpp

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Tags: addition binary-string bin

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Contributed on Apr 19 2022

Creepy Caribou

0 Answers Avg Quality 2/10

add binary strings

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string AddBinary(string a, string b)
{   
    var max = a.Length<b.Length ? b.Length : a.Length;

    var stack = new Stack<int>();
    var remainder = 0; 
    for (int i = 0; i < max; i++)
    {
        int x = 0,y=0;
        if(b.Length > i) x = (b[b.Length-i-1] =='0')?0:1;
        if(a.Length > i) y = (a[a.Length-i-1] == '0')? 0:1; 
        if((x^y)==1) stack.Push((remainder==1)?0:1); 
        else
        {
            stack.Push(remainder); 
            remainder = (x & y);
        }
    }  
    if(remainder!=0) stack.Push(remainder); 
    return string.Concat(stack); 
}

Popularity 10/10 Helpfulness 2/10 Language csharp

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Tags: add

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Contributed on Feb 14 2023

PrashantUnity

0 Answers Avg Quality 2/10

binary add using strings

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