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regex in r

Successful Salmon answered on January 29, 2022 Popularity 10/10 Helpfulness 4/10

answer regex in r

related regex in R

regex in r

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^ = Beginning of Line or String
$ = End of Line or String
. = Matches Anything like a Joker Card (inc blank spaces)
\\. = Escape the period when we search on an actual period

\\d or [::digit::] = 0, 1, 2, 3, ...
\\w or [::word::] = a, b, c, ..., 1, 2, 3, ..., _
[A-Za-z] or [::alpha::] = A, B, C, ... a, b, c, ...
[aeiou] = a, e, i, o, u
\\s or [::space::] = " ", tabs or line breaks

\\D = match all except digits
\\W = match all except word char (inc numbers and underscore)
\\S = match all except spaces, tabs or line breaks
[^A-Za-z] = match all except alphabet

\\d{2} = repeat digit exactly twice (double digit)
\\d{2, 3} = min repeat digit twice, max repeat 3 thrice
\\d{2,} = min repeat digit twice, no max 
\\d+ = 1 or more repetitions 
\\d* = 0, 1 or more repetitions 

| = OR (pattern = "apple|apples") [Not limited to 2 options only]
# No spaces are allowed within the vertical bar(s)
? = make the preceding group or character optional or
make the preceding multiplier "lazy" instead of "greedy".
Similar as above when coded as (pattern = apples?)

Greedy and Lazy [See Example 5a and b]
pattern = ".*3" (match everything before the last digit of 3)[Greedy]
pattern = ".*?3" (match only everything before the first digit of 3)[Lazy]

Examples:
1) Find all digits and spaces
stringr::str_match_all(x, pattern = "[\\d\\s]")

2) List all strings that end with a space followed by a digit
data[stringr::str_detect(x, pattern = "\\s\\d$")]

3) List all strings that contain "Grey" or "Gray"
data[stringr::str_detect(x, pattern = "Gr[ae]y")]

4) List all strings with strange characters (no word or space)
data[stringr::str_detect(x, pattern = "[^\\w\\s]")]

5) Greedy vs Lazy
	a) Greedy
	   >stringr::str_match("a 3 b 3 c", ".*3")
	   "a 3 b 3"
	b) Lazy
		>stringr::str_match("a 3 b 3 c", ".*?3")
		"a 3"

6) Three or more word characters, followed by an at-sign, 
one or more word characters and a ."com".
pattern = "\\w{3,}@\\w+\\.com"

Popularity 10/10 Helpfulness 4/10 Language r

Source: campus.datacamp.com

Tags: r regex

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Contributed on Jan 29 2022

Successful Salmon

0 Answers Avg Quality 2/10

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x <- "1888 is the longest year in Roman numerals: MDCCCLXXXVIII"
str_extract(x, "CC?")
#> [1] "CC"
str_extract(x, "CC+")
#> [1] "CCC"
str_extract(x, 'C[LX]+')
#> [1] "CLXXX"

Popularity 10/10 Helpfulness 2/10 Language r

Source: stringr.tidyverse.org

Tags: r

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Contributed on Jun 03 2022

Aggressive Addax

0 Answers Avg Quality 2/10

regex in r

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