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leetcode python

Relieved Ratel answered on February 9, 2022 Popularity 10/10 Helpfulness 1/10

answer leetcode python

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leetcode python

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def merge(self, nums1, m, nums2, n):
        while m > 0 and n > 0:
            if nums1[m-1] >= nums2[n-1]:
                nums1[m+n-1] = nums1[m-1]
                m -= 1
            else:
                nums1[m+n-1] = nums2[n-1]
                n -= 1
        if n > 0:
            nums1[:n] = nums2[:n]

Popularity 10/10 Helpfulness 1/10 Language python

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Tags: python

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Contributed on Feb 09 2022

Relieved Ratel

0 Answers Avg Quality 2/10

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# Solution for Leetcode1: Two Sum problem
# Time complexity: O(n) and Space complexity: O(n)
# n is the size of the input list, namely nums

"""
Given an array of integers nums and an integer target, 
return indices of the two numbers such that they add up to target.
"""
class Solution:
    def twoSum(self, nums: List[int], target: int) -> List[int]:
        hashmap = {}
        for i in range(len(nums)):
            complement = target - nums[i]
            if complement in hashmap:
                return [i, hashmap[complement]]
            hashmap[nums[i]] = i

Popularity 10/10 Helpfulness 2/10 Language python

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Tags: python py

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Contributed on Feb 10 2022

Wissam

0 Answers Avg Quality 2/10

leetcode solutions python

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-1

Python solution for Leetcode
Python solution of problems from LeetCode.

https://github.com/Garvit244/Leetcode

Popularity 10/10 Helpfulness 1/10 Language python

Source: github.com

Tags: python py

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Contributed on May 05 2022

Baggi

0 Answers Avg Quality 2/10

leetcode python

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