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quadratic equation calculator

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DifficultBozo answered on February 21, 2022 Popularity 10/10 Helpfulness 2/10

answer quadratic equation calculator

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quadratic equation calculator

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import tkinter as tk
import cmath

root= tk.Tk()

root.title("Quadratic Solver")

canvas1 = tk.Canvas(root, width = 400, height = 300)
canvas1.pack()

entry1 = tk.Entry (root) 
canvas1.create_window(200, 60, window=entry1)

entry2 = tk.Entry (root) 
canvas1.create_window(200, 100, window=entry2)

entry3 = tk.Entry (root) 
canvas1.create_window(200, 140, window=entry3)


def solvequadratic ():
    a = int(entry1.get())
    b = int(entry2.get())
    c = int(entry3.get())

    label1 = tk.Label(root, text= ((-b-cmath.sqrt((b**2)-(4*a*c))/(2*a))))
    canvas1.create_window(200, 230, window=label1)
    label1 = tk.Label(root, text = ((-b+cmath.sqrt((b**2)-(4*a*c))/(2*a))))
    canvas1.create_window(200, 260, window=label1)
    
button1 = tk.Button(text='Solve Quadratic', command=solvequadratic)
canvas1.create_window(200, 180, window=button1)

root.mainloop()

Popularity 10/10 Helpfulness 2/10 Language python

Source: Grepper

Tags: calculator equation python quadratic

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Contributed on Feb 21 2022

DifficultBozo

0 Answers Avg Quality 2/10

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quadratic equation solver

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import cmath

def solve_quadratic(a, b, c):
    # Calculate the discriminant
    discriminant = (b**2) - (4*a*c)

    # Find two solutions
    solution1 = (-b - cmath.sqrt(discriminant)) / (2*a)
    solution2 = (-b + cmath.sqrt(discriminant)) / (2*a)

    return solution1, solution2

# Example usage
a = 1
b = -5
c = 6
solution1, solution2 = solve_quadratic(a, b, c)

print("Solutions: {0} and {1}".format(solution1, solution2))

Popularity 10/10 Helpfulness 1/10 Language python

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Contributed on Sep 12 2023

YOU.com

0 Answers Avg Quality 2/10

quadratic equation formula

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import math

def solve_quadratic_equation(a, b, c):
    discriminant = b**2 - 4*a*c
    
    if discriminant > 0:
        # Two distinct real roots
        root1 = (-b + math.sqrt(discriminant)) / (2*a)
        root2 = (-b - math.sqrt(discriminant)) / (2*a)
        return root1, root2
    elif discriminant == 0:
        # One real root
        root = -b / (2*a)
        return root
    else:
        # Complex roots
        real_part = -b / (2*a)
        imaginary_part = math.sqrt(abs(discriminant)) / (2*a)
        root1 = complex(real_part, imaginary_part)
        root2 = complex(real_part, -imaginary_part)
        return root1, root2

# Example usage with coefficients a, b, and c
a = 1
b = -3
c = 2

roots = solve_quadratic_equation(a, b, c)
print("Roots:", roots)

Popularity 10/10 Helpfulness 1/10 Language python

Source: Grepper

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Contributed on Sep 12 2023

YOU.com

0 Answers Avg Quality 2/10

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