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Lucky Four codechef solution in c++

coder answered on May 22, 2020 Popularity 2/10 Helpfulness 1/10

answer Lucky Four codechef solution in c++

Lucky Four codechef solution in c++

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------------------------------------------------------------------------------------------
//solution<1>:
------------------------------------------------------------------------------------------
#include<iostream>
#include<string>
using namespace std;

int main()
{
	int t, n, count;
	cin >> t;
	for (int i = 0; i < t; i++)
	{
		cin >> n;
		string s = to_string(n);
		count = 0;
		for (int i = 0; i < s.length(); i++)
		{
			if (s[i] == '4')
				count++;
		}
		cout << count << "\n";
	}
	return 0;
}
------------------------------------------------------------------------------------------
//solution<2>:
------------------------------------------------------------------------------------------
#include<iostream>
using namespace std;

int main()
{
	int t, n, count, x;
	cin >> t;
	for (int i = 0; i < t; i++)
	{
		cin >> n;
		count = 0;
		while(n!=0)
		{
			x = n % 10;
			if (x == 4)
			{
				count++;
			}
			n /= 10;
		}
		cout << count << "\n";
	}
	return 0;
}

Popularity 2/10 Helpfulness 1/10 Language cpp

Source: www.codegrepper.com

Tags: c++ solution

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Contributed on Mar 07 2022

coder

0 Answers Avg Quality 2/10

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Lucky four codechef solution

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t=int(input())
a=str(4)
for i in range(t):
  x=str(input())
  count=0
  for j in x:
    if j==a:
      count=count+1
   print(count)

Popularity 6/10 Helpfulness 2/10 Language python

Source: Grepper

Tags: python solution

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Contributed on May 22 2020

Homeless Hawk

0 Answers Avg Quality 2/10

Lucky Four codechef solution in c++

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Lucky Four codechef solution in c++

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Lucky four codechef solution

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