int [] arr = {1,1,1,2,2,2,3,3,3,4,4,5,5,6,7,8,};

for (int j= 0; j < arr.length; j++){
int count1 = 0; // to find out how many time value is appeared in the arry
for (int i = 0; i < arr.length; i++){
     if(arr[i] == arr[j] ) {    
    // if(arr[i] == 1 ) { once boyleydi ikinci for gelince soldaki oldu
      count1++; // arraydeki harfleri tek tek saymak icin
  }
 }
    if(count1 == 1 ){
    System.out.print(arr[j]+" ");// 6 7 8 uniqe
 }

Popularity 9/10 Helpfulness 4/10 Language java

Source: Grepper

Tags: elements element

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Contributed on Jun 04 2021

Ozzzy

0 Answers Avg Quality 2/10

unique numbers in array java

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for (int j= 0; j < arr.length; j++){
int count1 = 0; // to find out how many time value is appeared in the arry
for (int i = 0; i < arr.length; i++){
     if(arr[i] == arr[j] ) {    
    // if(arr[i] == 1 ) { once boyleydi ikinci for gelince soldaki oldu
      count1++; // arraydeki harfleri tek tek saymak icin
  }
 }
    if(count1 == 1 ){
    System.out.print(arr[j]+" ");// 6 7 8 uniqe
 }

Popularity 1/10 Helpfulness 1/10 Language java

Source: Grepper

Tags: java numbers unique

Link to this answer
Share Copy Link

Contributed on Mar 15 2022

shivatmika reddy

0 Answers Avg Quality 2/10

unique numbers in array java

Comment

1 6 6 6

Popularity 1/10 Helpfulness 1/10 Language java

Source: Grepper

Tags: java numbers unique

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Contributed on Aug 21 2022

Shwe Phoo

0 Answers Avg Quality 2/10

unique numbers in array java

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