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rust•armanriazi•error•panicked•at 'already borrowed: BorrowMutError'

ArmanRiazi answered on March 9, 2022 Popularity 1/10 Helpfulness 1/10

answer rust•armanriazi•error•panicked•at 'already borrowed: BorrowMutError'

related armanriazi•rust•error•already borrowed: BorrowMutError

rust•armanriazi•error•panicked•at 'already borrowed: BorrowMutError'

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If we try to violate these rules, rather than getting a compiler error as we would with references, the implementation of RefCell<T> will panic at runtime.
We’re deliberately trying to create two mutable borrows active for the same scope to illustrate that RefCell<T> prevents us from doing this at runtime.
 //+//let mut one_borrow = self.sent_messages.borrow_mut();
 //-//let mut two_borrow = self.sent_messages.borrow_mut();

Popularity 1/10 Helpfulness 1/10 Language rust

Source: Grepper

Tags: rust

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Contributed on Mar 25 2022

ArmanRiazi

0 Answers Avg Quality 2/10

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armanriazi•rust•error•already borrowed: BorrowMutError

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   let mut base_3 = base.borrow_mut();
   base_3.radio_freq += 43.21; //** main issue. you need to define this line in interior block like line scope 7 so line 2 is wrong when placed in main scope
 
   println!("base: {:?}", base);
   println!("base_3: {:?}", base_3);

   {
    let mut base_4 = base.borrow_mut();//'already borrowed: BorrowMutError'
    base_4.radio_freq -= 3.52;
    println!("base_2: {:?}", base_4);
   }
   
   /*
   base: RefCell { value: <borrowed> }  //**
   base_3: GroundStation { radio_freq: 118.52000000000001 }
   thread 'main' panicked at 'already borrowed: BorrowMutError'
   */

Popularity 1/10 Helpfulness 1/10 Language rust

Source: Grepper

Tags: rust

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Contributed on Mar 09 2022

ArmanRiazi

0 Answers Avg Quality 2/10

rust•armanriazi•error•panicked•at 'already borrowed: BorrowMutError'

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