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continue function

MUHAMMAD UMAR answered on March 30, 2022 Popularity 7/10 Helpfulness 1/10

answer continue function

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continue function

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i = 1, j = 1
i = 1, j = 3
i = 2, j = 1
i = 2, j = 3
i = 3, j = 1
i = 3, j = 3

Popularity 7/10 Helpfulness 1/10 Language whatever

Source: www.programiz.com

Tags: continue function whatever

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Contributed on Mar 30 2022

MUHAMMAD UMAR

0 Answers Avg Quality 2/10

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continue function

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// program to calculate positive numbers till 50 only
// if the user enters a negative number,
// that number is skipped from the calculation

// negative number -> loop terminate
// numbers above 50 -> skip iteration

#include <iostream>
using namespace std;

int main() {
    int sum = 0;
    int number = 0;

    while (number >= 0) {
        // add all positive numbers
        sum += number;

        // take input from the user
        cout << "Enter a number: ";
        cin >> number;

        // continue condition
        if (number > 50) {
            cout << "The number is greater than 50 and won't be calculated." << endl;
            number = 0;  // the value of number is made 0 again
            continue;
        }
    }

    // display the sum
    cout << "The sum is " << sum << endl;

    return 0;
}

Popularity 8/10 Helpfulness 2/10 Language whatever

Source: www.programiz.com

Tags: whatever continue function functio

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Contributed on Mar 30 2022

MUHAMMAD UMAR

0 Answers Avg Quality 2/10

continue function

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Enter a number: 12
Enter a number: 0
Enter a number: 2
Enter a number: 30
Enter a number: 50
Enter a number: 56
The number is greater than 50 and won't be calculated.
Enter a number: 5
Enter a number: -3
The sum is 99

Popularity 7/10 Helpfulness 1/10 Language whatever

Source: www.programiz.com

Tags: continue whatever function whateve

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Contributed on Mar 30 2022

MUHAMMAD UMAR

0 Answers Avg Quality 2/10

continue function

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// using continue statement inside
// nested for loop

#include <iostream>
using namespace std;

int main() {
    int number;
    int sum = 0;

    // nested for loops

    // first loop
    for (int i = 1; i <= 3; i++) {
        // second loop
        for (int j = 1; j <= 3; j++) {
            if (j == 2) {
                continue;
            }
            cout << "i = " << i << ", j = " << j << endl;
        }
    }

    return 0;
}

Popularity 7/10 Helpfulness 1/10 Language whatever

Source: www.programiz.com

Tags: function continue whatever functio

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Contributed on Mar 30 2022

MUHAMMAD UMAR

0 Answers Avg Quality 2/10

continue function

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