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Appending rows to a DataFrame

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Gia Khanh Nguyen answered on April 20, 2020 Popularity 10/10 Helpfulness 4/10

answer Appending rows to a DataFrame

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Appending rows to a DataFrame

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s2 = pd.Series(["X0", "X1", "X2", "X3"], index=["A", "B", "C", "D"])

In [32]: result = pd.concat([df1, s2.to_frame().T], ignore_index=True)

Popularity 10/10 Helpfulness 4/10 Language python

Source: pandas.pydata.org

Tags: dataframe python rows

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Contributed on Apr 30 2022

Gia Khanh Nguyen

0 Answers Avg Quality 2/10

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add rows to dataframe pandas

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df = df.append({'a':1, 'b':2}, ignore_index=True)

Popularity 10/10 Helpfulness 7/10 Language python

Source: Grepper

Tags: add

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Contributed on Sep 21 2020

alberduris

0 Answers Avg Quality 2/10

add row to dataframe

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df = pd.concat([df, pd.DataFrame([new_row])], ignore_index=True)

Popularity 8/10 Helpfulness 7/10 Language python

Source: Grepper

Tags: add dataframe data

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Contributed on Jun 13 2024

Markhor

0 Answers Avg Quality 2/10

pandas add row to pandas dataframe

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# Basic syntax using .loc:
df.loc[len(df.index)] = ['col1_val', 'col2_val', '...']
# Where:
#	- len(df.index) gets the number of rows in the dataframe. Because the index
#		uses 0 indexing, the length is 1 more than the number of rows.
#	- .loc[] is used to access rows and columns of the dataframe by their
#		label(s). In this case, because the length is 1 more than the number
#		of rows, we're effectively saying "add a new row with an index label
#		that is 1 more than the bottom row".

# Basic syntax using .concat:
df = pd.concat([df, pd.DataFrame([{'col1_name': 'col1_val', 'col2_name': 'col2_val', 'col3_name': '...'}])], ignore_index=True)

# Note, the .append method is deprecated now.

# Example usage using .loc:
import pandas as pd

# Make the dataframe
dict = {'Name':['Martha', 'Tim', 'Rob', 'Georgia'],
        'Maths':[87, 91, 97, 95],
        'Science':[83, 99, 84, 76]}
df = pd.DataFrame(dict)

# Add a row to it
df.loc[len(df.index)] = ['Amy', 89, 93] 
print(df)
-->       Name  Maths  Science
	0   Martha     87       83
	1      Tim     91       99
	2      Rob     97       84
	3  Georgia     95       76
	4      Amy     89       93

# Example usage using .concat:
import pandas as pd

# Make the dataframe
dict = {'Name':['Martha', 'Tim', 'Rob', 'Georgia'],
        'Maths':[87, 91, 97, 95],
        'Science':[83, 99, 84, 76]}
df = pd.DataFrame(dict)

# Add a row to it
df = pd.concat([df, pd.DataFrame([{'Name': 'Amy', 'Maths': 89, 'Science': 93}])], ignore_index=True)
print(df)
-->       Name  Maths  Science
    0   Martha     87       83
    1      Tim     91       99
    2      Rob     97       84
    3  Georgia     95       76
    4      Amy     89       93

Popularity 10/10 Helpfulness 6/10 Language python

Source: www.geeksforgeeks.org

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Contributed on Apr 20 2023

Charles-Alexandre Roy

0 Answers Avg Quality 2/10

add row to dataframe

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# Below are quick example

# add Row to DataFrame
list_row = ["Hyperion", 27000, "60days", 2000]
df.loc[len(df)] = list_row

# Insert Dict to the dataframe using DataFrame.append()
new_row = {'Courses':'Hyperion', 'Fee':24000, 'Duration':'55days', 'Discount':1800}
df2 = df.append(new_row, ignore_index=True)

# Add new row to specifig index name
df2 = df.append(pd.DataFrame([new_row],index=['7'],columns=df.columns))

# Append row to the DataFrame
df2 = df.append(pd.Series(new_row, index=df.columns, name='7'))

# Using pandas.concat() to add a row
new_row = pd.DataFrame({'Courses':'Hyperion', 'Fee':24000, 'Duration':'55days', 'Discount':1800}, index=[0])
df2 = pd.concat([new_row,df.loc[:]]).reset_index(drop=True)

# Add specific row/index name using DataFrame.loc[]
df.loc['7', :] = ['Hive',25000,'45days',2000]

# Add row in DataFrame using DataFrame.loc[]
df.loc['7'] = ['Hive',25000,'45days',2000]

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Source: sparkbyexamples.com

Tags: add

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Contributed on Nov 28 2022

Funny Flatworm

0 Answers Avg Quality 2/10

dataframe add row

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# append row to dataframe without index

a_row = pd.Series([1, 2])
df = pd.DataFrame([[3, 4], [5, 6]])

row_df = pd.DataFrame([a_row])
df = pd.concat([row_df, df], ignore_index=True)

print(df)
# OUTPUT
#    0  1
# 0  1  2
# 1  3  4
# 2  5  6

# append row to dataframe with index

a_row = pd.Series([1, 2])
df = pd.DataFrame([[3, 4], [5, 6]], index = ["row1", "row2"])

row_df = pd.DataFrame([a_row], index = ["row3"])
df = pd.concat([row_df, df])

print(df)
# OUTPUT
#       0  1
# row3  1  2
# row1  3  4
# row2  5  6

Popularity 10/10 Helpfulness 5/10 Language python

Source: www.kite.com

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Contributed on Aug 10 2021

Amused Ape

0 Answers Avg Quality 2/10

add one row to DataFrame

Comment

import pandas as pd
# One value for each column
df.loc[len(df.index)] = [value1, value2, value3]

Popularity 10/10 Helpfulness 5/10 Language python

Source: Grepper

Tags: dataframe data

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Contributed on Aug 25 2022

JJSSEEXX

0 Answers Avg Quality 2/10

add new row to dataframe pandas

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# Add a new row at index k with values provided in list
dfObj.loc['k'] = ['Smriti', 26, 'Bangalore', 'India']

Popularity 10/10 Helpfulness 4/10 Language python

Source: thispointer.com

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Contributed on Apr 20 2020

Nasty Newt

0 Answers Avg Quality 2/10

Appending rows to a DataFrame

Comment

s2 = pd.Series(["X0", "X1", "X2", "X3"], index=["A", "B", "C", "D"])

In [32]: result = pd.concat([df1, s2.to_frame().T], ignore_index=True)

Popularity 10/10 Helpfulness 4/10 Language python

Source: pandas.pydata.org

Tags: dataframe data

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Contributed on Apr 30 2022

Gia Khanh Nguyen

0 Answers Avg Quality 2/10

Appending rows to a DataFrame

Comment

-1

s2 = pd.Series(["X0", "X1", "X2", "X3"], index=["A", "B", "C", "D"])

In [32]: result = pd.concat([df1, s2.to_frame().T], ignore_index=True)

Popularity 10/10 Helpfulness 3/10 Language python

Source: pandas.pydata.org

Tags: dataframe data

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Contributed on Apr 30 2022

Gia Khanh Nguyen

0 Answers Avg Quality 2/10

Appending rows to a DataFrame

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