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find the second aperrence of a char in string c++

ShakedCode answered on May 5, 2022 Popularity 1/10 Helpfulness 1/10

answer find the second aperrence of a char in string c++

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find the second aperrence of a char in string c++

Comment

#include <string>

int nthOccurrence(const std::string& str, const std::string& findMe, int nth)
{
    size_t  pos = 0;
    int     cnt = 0;

    while( cnt != nth )
    {
        pos+=1;
        pos = str.find(findMe, pos);
        if ( pos == std::string::npos )
            return -1;
        cnt++;
    }
    return pos;
}

Popularity 1/10 Helpfulness 1/10 Language cpp

Source: stackoverflow.com

Tags: c++ char find string

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Contributed on May 05 2022

ShakedCode

0 Answers Avg Quality 2/10

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find the second aperrence of a char in string c++

Comment

#include <string>

int nthOccurrence(const std::string& str, const std::string& findMe, int nth)
{
    size_t  pos = 0;
    int     cnt = 0;

    while( cnt != nth )
    {
        pos+=1;
        pos = str.find(findMe, pos);
        if ( pos == std::string::npos )
            return -1;
        cnt++;
    }
    return pos;
}

Popularity 1/10 Helpfulness 1/10 Language cpp

Source: stackoverflow.com

Tags: c++ char find string

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Contributed on May 05 2022

ShakedCode

0 Answers Avg Quality 2/10

find the second aperrence of a char in string c++

Comment

#include <string>

int nthOccurrence(const std::string& str, const std::string& findMe, int nth)
{
    size_t  pos = 0;
    int     cnt = 0;

    while( cnt != nth )
    {
        pos+=1;
        pos = str.find(findMe, pos);
        if ( pos == std::string::npos )
            return -1;
        cnt++;
    }
    return pos;
}

Popularity 1/10 Helpfulness 1/10 Language cpp

Source: stackoverflow.com

Tags: find string c++ char

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Contributed on May 05 2022

ShakedCode

0 Answers Avg Quality 2/10

find the second aperrence of a char in string c++

Comment

#include <string>

int nthOccurrence(const std::string& str, const std::string& findMe, int nth)
{
    size_t  pos = 0;
    int     cnt = 0;

    while( cnt != nth )
    {
        pos+=1;
        pos = str.find(findMe, pos);
        if ( pos == std::string::npos )
            return -1;
        cnt++;
    }
    return pos;
}

Popularity 1/10 Helpfulness 1/10 Language cpp

Source: stackoverflow.com

Tags: find string c++ char

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Contributed on May 05 2022

ShakedCode

0 Answers Avg Quality 2/10

find the second aperrence of a char in string c++

Comment

#include <string>

int nthOccurrence(const std::string& str, const std::string& findMe, int nth)
{
    size_t  pos = 0;
    int     cnt = 0;

    while( cnt != nth )
    {
        pos+=1;
        pos = str.find(findMe, pos);
        if ( pos == std::string::npos )
            return -1;
        cnt++;
    }
    return pos;
}

Popularity 1/10 Helpfulness 1/10 Language cpp

Source: stackoverflow.com

Tags: c++ char find string

Link to this answer
Share Copy Link

Contributed on May 05 2022

ShakedCode

0 Answers Avg Quality 2/10

find the second aperrence of a char in string c++

Comment

#include <string>

int nthOccurrence(const std::string& str, const std::string& findMe, int nth)
{
    size_t  pos = 0;
    int     cnt = 0;

    while( cnt != nth )
    {
        pos+=1;
        pos = str.find(findMe, pos);
        if ( pos == std::string::npos )
            return -1;
        cnt++;
    }
    return pos;
}

Popularity 1/10 Helpfulness 1/10 Language cpp

Source: stackoverflow.com

Tags: c++ char find string

Link to this answer
Share Copy Link

Contributed on May 05 2022

ShakedCode

0 Answers Avg Quality 2/10

find the second aperrence of a char in string c++

Comment

#include <string>

int nthOccurrence(const std::string& str, const std::string& findMe, int nth)
{
    size_t  pos = 0;
    int     cnt = 0;

    while( cnt != nth )
    {
        pos+=1;
        pos = str.find(findMe, pos);
        if ( pos == std::string::npos )
            return -1;
        cnt++;
    }
    return pos;
}

Popularity 1/10 Helpfulness 1/10 Language cpp

Source: stackoverflow.com

Tags: c++ char find string

Link to this answer
Share Copy Link

Contributed on May 05 2022

ShakedCode

0 Answers Avg Quality 2/10

find the second aperrence of a char in string c++

Comment

#include <string>

int nthOccurrence(const std::string& str, const std::string& findMe, int nth)
{
    size_t  pos = 0;
    int     cnt = 0;

    while( cnt != nth )
    {
        pos+=1;
        pos = str.find(findMe, pos);
        if ( pos == std::string::npos )
            return -1;
        cnt++;
    }
    return pos;
}

Popularity 1/10 Helpfulness 1/10 Language cpp

Source: stackoverflow.com

Tags: c++ char find string

Link to this answer
Share Copy Link

Contributed on May 05 2022

ShakedCode

0 Answers Avg Quality 2/10

find the second aperrence of a char in string c++

Comment

#include <string>

int nthOccurrence(const std::string& str, const std::string& findMe, int nth)
{
    size_t  pos = 0;
    int     cnt = 0;

    while( cnt != nth )
    {
        pos+=1;
        pos = str.find(findMe, pos);
        if ( pos == std::string::npos )
            return -1;
        cnt++;
    }
    return pos;
}

Popularity 1/10 Helpfulness 1/10 Language cpp

Source: stackoverflow.com

Tags: string c++ char find

Link to this answer
Share Copy Link

Contributed on May 05 2022

ShakedCode

0 Answers Avg Quality 2/10

find the second aperrence of a char in string c++

Comment

#include <string>

int nthOccurrence(const std::string& str, const std::string& findMe, int nth)
{
    size_t  pos = 0;
    int     cnt = 0;

    while( cnt != nth )
    {
        pos+=1;
        pos = str.find(findMe, pos);
        if ( pos == std::string::npos )
            return -1;
        cnt++;
    }
    return pos;
}

Popularity 1/10 Helpfulness 1/10 Language cpp

Source: stackoverflow.com

Tags: c++ char find string

Link to this answer
Share Copy Link

Contributed on May 05 2022

ShakedCode

0 Answers Avg Quality 2/10

find the second aperrence of a char in string c++

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find the second aperrence of a char in string c++

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