Breaking News: Grepper is joining You.com. Read the official announcement!

javascript call flask function

Add Answer

Emre Önal answered on April 28, 2021 Popularity 9/10 Helpfulness 1/10

answer javascript call flask function

related call javascript function flask

related javascript function from python flask

related call javascript function from flask

javascript call flask function

Comment

from flask import Flask, jsonify, render_template, request
app = Flask(__name__)


@app.route('/')
def index():
    return render_template('index.html')

@app.route('/SomeFunction')
def SomeFunction():
    print('In SomeFunction')
    return "Nothing"



if __name__ == '__main__':
   app.run()

Popularity 9/10 Helpfulness 1/10 Language javascript

Source: Grepper

Tags: call flask function javascript

Link to this answer
Share Copy Link

Contributed on May 07 2022

Emre Önal

0 Answers Avg Quality 2/10

Closely Related Answers

call javascript function flask

Comment

from flask import Flask, render_template

app = Flask(__name__)


@app.route('/', methods=['GET', 'POST'])
def upload_file():
    if request.method == 'POST':
        #verify if the file is valid
        #here invoke js to do something (for example flash("test"))
        return render_template('upload.html', flash_message="True")

    return render_template('upload.html', flash_message="False")

Popularity 9/10 Helpfulness 2/10 Language python

Source: stackoverflow.com

Tags: call

Link to this answer
Share Copy Link

Contributed on Apr 28 2021

Huy Nguyen

0 Answers Avg Quality 2/10

javascript function from python flask

Comment

<!DOCTYPE html>
<html lang="en">
<head>
  <meta charset="UTF-8">
  <title>Upload new File</title>
</head>
<body onload="flashMessage()">
  <script>
    function flashMessage() {
      if ("{{ flash_message }}" == "True") {
        alert("[YOUR_MESSAGE_HERE]");
      }
    }
  </script>

  <h1>Upload new File</h1>
  <form method=post enctype=multipart/form-data>
    <input type=file name=file>
    <input type=submit value=Upload>
  </form>
</body>
</html>

Popularity 9/10 Helpfulness 2/10 Language whatever

Source: stackoverflow.com

Tags: flask flas

Link to this answer
Share Copy Link

Contributed on Oct 13 2021

Plain Pheasant

0 Answers Avg Quality 2/10

call javascript function from flask

Comment

from flask import Flask, render_template

app = Flask(__name__)


@app.route('/', methods=['GET', 'POST'])
def upload_file():
    if request.method == 'POST':
        #verify if the file is valid
        #here invoke js to do something (for example flash("test"))
        return render_template('upload.html', flash_message="True")

    return render_template('upload.html', flash_message="False")

Popularity 7/10 Helpfulness 1/10 Language javascript

Source: Grepper

Tags: call flask javascript j

Link to this answer
Share Copy Link

Contributed on May 06 2022

ofroog

0 Answers Avg Quality 2/10

javascript call flask function

Contents

More Related Answers

javascript call flask function

Closely Related Answers

call javascript function flask

javascript function from python flask

call javascript function from flask

Grepper

Documentation

Social

Legal

Contact

Oops, You will need to install Grepper and log-in to perform this action.