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Show output of views in html using ajax, django

Incursio answered on May 24, 2022 Popularity 3/10 Helpfulness 1/10

answer Show output of views in html using ajax, django

Show output of views in html using ajax, django

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#views.py
def ajaxUpload(request):
    predictedLabel = predictimage(request)
    print("success")
    context = {"predictedLabel": predictedLabel}
    return HttpResponse(json.dumps(context)) #dump the context into json
  
#javaScript
$("#theForm").submit(function uploadFile(e){
            e.preventDefault();
            var data=new FormData();
             data.append("file",$("#inpFile")[0].files[0]);
             data.append("csrfmiddlewaretoken", "{{csrf_token}}");
             $.ajax({
                 method:"POST",
                 url:"/ajaxupload/",
                 processData:false,
                 contentType:false,
                 mimeType:"multipart/form-data",
                 data:data,
                 success:function(response){
                    var obj=JSON.parse(response)["predictedLabel"]; #parse the json with name of the context you want
                    $("#predictedOutput").text(obj)
                 }
             })
        })

Popularity 3/10 Helpfulness 1/10 Language python

Source: stackoverflow.com

Tags: django html output python show using

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