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Java Scanner nextLine()

SAMER SAEID answered on August 24, 2020 Popularity 8/10 Helpfulness 5/10

answer Java Scanner nextLine()

related java scanner string nextline after nextint

Java Scanner nextLine()

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import java.util.Scanner;

class Main {
  public static void main(String[] args) {

    // creates an object of Scanner
    Scanner input = new Scanner(System.in);
    System.out.print("Enter your name: ");

    // reads the entire line
    String value = input.nextLine();
    System.out.println("Using nextLine(): " + value);

    input.close();
  }
}

Popularity 8/10 Helpfulness 5/10 Language java

Source: Grepper

Tags: java

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Contributed on May 25 2022

SAMER SAEID

0 Answers Avg Quality 2/10

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java scanner string nextline after nextint

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//The problem is with the input.nextInt() method - it only reads the int value. So when you continue reading with input.nextLine() you receive the "\n" Enter key. So to skip this you have to add the input.nextLine(). Hope this should be clear now.

//Try it like that:

System.out.print("Insert a number: ");
int number = input.nextInt();
input.nextLine(); // This line you have to add (It consumes the \n character)
System.out.print("Text1: ");
String text1 = input.nextLine();
System.out.print("Text2: ");
String text2 = input.nextLine();

Popularity 10/10 Helpfulness 4/10 Language java

Source: stackoverflow.com

Tags: java

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Contributed on Aug 24 2020

DevPedrada

0 Answers Avg Quality 2/10

Java Scanner nextLine()

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Java Scanner nextLine()

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java scanner string nextline after nextint

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