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Python re.findall()

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SAMER SAEID answered on July 16, 2020 Popularity 10/10 Helpfulness 2/10

answer Python re.findall()

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Python re.findall()

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# Program to extract numbers from a string

import re

string = 'hello 12 hi 89. Howdy 34'
pattern = '\d+'

result = re.findall(pattern, string) 
print(result)

# Output: ['12', '89', '34']

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Contributed on May 27 2022

SAMER SAEID

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Python RegEx Findall – re.findall()

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# A Python program to demonstrate working of findall()
import re

# A sample text string where regular expression is searched.
string = """Todays date is 27 , month is 05 and year is 2022"""

# A sample regular expression to find digits.
regex = '\d+'

match = re.findall(regex, string)
print(match)

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Source: softhunt.net

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Contributed on Jun 05 2022

Outrageous Ostrich

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python .findall

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  ## Search for pattern 'bb' in string 'aabbcc'.
  ## All of the pattern must match, but it may appear anywhere.
  ## On success, match.group() is matched text.
  match = re.search(r'bb', 'aabbcc') # found, match.group() == "bb"
  match = re.search(r'cd', 'aabbcc') # not found, match == None

  ## . = any char but \n
  match = re.search(r'...c', 'aabbcc') # found, match.group() == "abbc"

  ## \d = digit char, \w = word char
  match = re.search(r'\d\d\d', 'p123g') # found, match.group() == "123"
  match = re.search(r'\w\w\w', '@@abcd!!') # found, match.group() == "abc"

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Contributed on Jul 16 2020

Colorful Capuchin

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Python re.findall()

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