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import itertools
list1 = list(range(5, 10))
list2 = [1, 2, 3]
list = [list1, list2]
combination = [p for p in itertools.product(*list)]
print(combination)
PythonCopy
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# 1. Print all combinations
from itertools import combinations
comb = combinations([1, 1, 3], 2)
print(list(combinations([1, 2, 3], 2)))
# Output: [(1, 2), (1, 3), (2, 3)]
# 2. Counting combinations
from math import comb
print(comb(10,3))
#Output: 120
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import itertools
stuff = [1, 2, 3]
for L in range(len(stuff) + 1):
for subset in itertools.combinations(stuff, L):
print(subset)
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from itertools import combinations
school_subjects = ["math", "science", "history", "geography", "language arts", "Spanish"]
num_per_combos = 3
combos = list(combinations(school_subjects, num_per_combos))
for lists in combos:
for combo in lists:
print(combo + " ")
print("\n")
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import itertools
def subs(l):
res = []
for i in range(1, len(l) + 1):
for combo in itertools.combinations(l, i):
res.append(list(combo))
return res
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all_combinations = [list(zip(each_permutation, list2)) for each_permutation in itertools.permutations(list1, len(list2))]
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def combinations(iterable, r):
pool = tuple(iterable)
n = len(pool)
for indices in permutations(range(n), r):
if sorted(indices) == list(indices):
yield tuple(pool[i] for i in indices)