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Palindrome

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Breakable Boar answered on November 23, 2020 Popularity 9/10 Helpfulness 2/10

answer Palindrome

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Palindrome

Comment

import java.util.Scanner;
class Palindrome {
    public static void main(String args[]) {
        String original, reverse = "";
        Scanner s1 = new Scanner(System.in);
        System.out.println("Enter a word");
        original = "cat";
        int length = original.length();
        for ( int i = length - 1; i >= 0; i-- )
            reverse = reverse + original.charAt(i);
        if (original.equals(reverse))
            System.out.println("true");
        else
            System.out.println("false");
    }
}

Popularity 9/10 Helpfulness 2/10 Language java

Source: Grepper

Tags: java palindrome

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Contributed on Jun 12 2022

Breakable Boar

0 Answers Avg Quality 2/10

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palindrome

Comment

function isPalindrome(sometext) {
  var replace = /[.,'!?\- \"]/g; //regex for what chars to ignore when determining if palindrome
  var text = sometext.replace(replace, '').toUpperCase(); //remove toUpperCase() for case-sensitive
  for (var i = 0; i < Math.floor(text.length/2) - 1; i++) {
    if(text.charAt(i) == text.charAt(text.length - 1 - i)) {
      continue;
    } else {
      return false;
    }
  }
  return true;
}
//EDIT: found this on https://medium.com/@jeanpan/javascript-splice-slice-split-745b1c1c05d2
//, it is much more elegant:
function isPalindrome(str) {
  return str === str.split('').reverse().join(''); 
}
//you can still add the regex and toUpperCase() if you don't want case sensitive

Popularity 10/10 Helpfulness 2/10 Language javascript

Source: Grepper

Tags: javascript j

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Contributed on Nov 23 2020

Google

0 Answers Avg Quality 2/10

Palindrome check

Comment

bool isPalindrom(string str){
    for (int i = 0; i < str.length(); i++)
       if(str[i]!=str[str.length()-i]) return false;
    return true;
}

Popularity 10/10 Helpfulness 2/10 Language cpp

Source: Grepper

Tags: c++

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Contributed on Sep 26 2023

Shishir Bhuiyan

0 Answers Avg Quality 2/10

palindrome

Comment

#palindrome program in python
n=int(input('Enter a number :'))
num=n
rev=0

while n>0:
 r=n%10
 rev=rev*10+r
 n//=10
print('Reverse of',num,'=',rev)
if rev==num:
  print(num,'is a palindrome number')
else :
  print(num,'is not a palindrome number')
#output
Enter a number :132
Reverse of 132 = 231
132 is not a palindrome numbe
________________________________________________________________________________
Enter a number :451
Reverse of 451 = 154
451 is not a palindrome number
________________________________________________________________________________
Enter a number :12321
Reverse of 12321 = 12321
12321 is a palindrome number

Popularity 10/10 Helpfulness 2/10 Language python

Source: Grepper

Tags: palindrome p

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Contributed on Dec 22 2021

Gr@Y_orphan_ViLL@in##

0 Answers Avg Quality 2/10

Palindrome Number

Comment

class Solution {
    public boolean isPalindrome(int x) {
        
    }
}

Popularity 10/10 Helpfulness 2/10 Language java

Source: Grepper

Tags: java

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Contributed on Aug 17 2022

CodeBlack reactor

0 Answers Avg Quality 2/10

palindrome

Comment

def is_palindrome(s):
    string = s
    if (string==string[::-1]):
        print("The string IS a palindrome")
    else:
        print("The string is NOT a palindrome")
    return

Popularity 9/10 Helpfulness 2/10 Language python

Source: stackoverflow.com

Tags: palindrome p

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Contributed on Oct 14 2022

Alex Vornicu

0 Answers Avg Quality 2/10

palindrome

Comment

var letters = [];
var word = "racecar"  //bob

var rword = "";

//put letters of word into stack
for (var i = 0; i < word.length; i++) {
    letters.push(word[i]);
}

//pop off the stack in reverse order
for (var i = 0; i < word.length; i++) {
    rword += letters.pop();
}

if (rword === word) {
    console.log("The word is a palindrome");
}
else {
    console.log("The word is not a palindrome");
}

Popularity 10/10 Helpfulness 2/10 Language javascript

Source: Grepper

Tags: javascript j

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Contributed on Jun 10 2022

Edicemi

0 Answers Avg Quality 2/10

palindrome

Comment

# Program to check if a string is palindrome or not

my_str = 'aIbohPhoBiA'

# make it suitable for caseless comparison
my_str = my_str.casefold()

# reverse the string
rev_str = reversed(my_str)

# check if the string is equal to its reverse
if list(my_str) == list(rev_str):
   print("The string is a palindrome.")
else:
   print("The string is not a palindrome.")

Popularity 9/10 Helpfulness 2/10 Language python

Source: www.programiz.com

Tags: palindrome p

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Contributed on Jul 26 2022

Jinn world

0 Answers Avg Quality 2/10

Palindrome Number

Comment

var isPalindrome = function(x) {
    
let y = x
let r = y.toString().split('').reverse().join('')

let t = Number(r)

if(t ===x){
  return true
}
else{ 
  return false}


}

Popularity 10/10 Helpfulness 2/10 Language javascript

Source: Grepper

Tags: javascript j

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Contributed on Jun 28 2022

ABS

0 Answers Avg Quality 2/10

palindrome

Comment

# Note: A palindrome is a string that reads the same forwards and backwards.
def palindrome_function(original_list, user_string):
    # reversing the list
    reversed_list = original_list[::-1]

    # comparing reversed_list to original_list to
    # determine if the original_list is a palindrome
    if reversed_list == original_list:
        print("'" + user_string.lower() + "' is a palindrome.")
    else:
        print("'" + user_string.lower() + "' is not a palindrome!")
        
        
def main():
    # promting user to input a word or phrase
    user_string = input("Enter string: ")
    
    user_list = list(user_string.lower())

	# putting our palindrome_function() to use
    palindrome_function(user_list, user_string)


if __name__ == "__main__":
    main()

Popularity 9/10 Helpfulness 2/10 Language python

Source: Grepper

Tags: palindrome p

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Contributed on Jun 28 2022

Weary Warbler

0 Answers Avg Quality 2/10

palindrome

Comment

function isPalindrome(word) {
	// Step 1- Put a pointer at each extreme of the word
    // Step 2 - Iterate the string "inwards"
	// Step 3 - At each iteration, check if the pointers represent equal values
	// If this condition isn't accomplished, the word isn't a palindrome
    let left = 0
    let right = word.length-1

    while (left < right) {
        if (word[left] !== word[right]) return false
        left++
        right--
    }
    
    return true
}

isPalindrome("neuquen") // true
isPalindrome("Buenos Aires") // false

Popularity 9/10 Helpfulness 2/10 Language whatever

Source: www.freecodecamp.org

Tags: palindrome p

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Contributed on Sep 02 2022

David Junior

0 Answers Avg Quality 2/10

Palindrome

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