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Go Channel

SAMER SAEID answered on June 16, 2022 Popularity 9/10 Helpfulness 2/10

answer Go Channel

related go channel

Go Channel

Comment

package main
import "fmt"

func main() {
  
  // create channel of integer type
   number := make(chan int)
 
  // access type and value of channel
  fmt.Printf("Channel Type: %T\n", number)
  fmt.Printf("Channel Value: %v", number)

}

Popularity 9/10 Helpfulness 2/10 Language go

Source: Grepper

Tags: channel go

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Contributed on Jun 16 2022

SAMER SAEID

0 Answers Avg Quality 2/10

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go channel

Comment

package main

import (
	"fmt"
	"time"
)

func main() {
	channelImmutable()
}

// -> you use only allow one channel capacity, but you use 2 capacity, channel can be blocked
// for handle this issue, you must create channel to zero value, like this <- ch
func channelImmutable() {
	ch := make(chan string, 1)
	ch <- "marwan"
	<-ch
	ch <- "jajang"

	fmt.Println("channelOne", <-ch) // and i can print jajang not marwan and this can't be blocked
}

// channelOne print value, with declare to variable channel;
func channelOne() {
	ch := make(chan string, 2)
	ch <- "marwan"
	ch <- "jajang"

	fmt.Println("channelOne", <-ch)
	fmt.Println("channelOne", <-ch)
}

// channelTwo print value and wrapper with gorutine, because with you use loop range not using gorutine channel is blocked, because you print more channel
func channelTwo() {
	ch := make(chan string, 2)
	ch <- "marwan"
	ch <- "jajang"

	go func() {
		for v := range ch {
			fmt.Println(v)
		}
	}()
	time.Sleep(time.Second * 1)
}

// channelThree print value without gorutine, but with loop and length channel
func channelThree() {
	ch := make(chan string, 2)
	ch <- "marwan"
	ch <- "jajang"

	for i := 0; i <= len(ch); i++ {
		fmt.Println(<-ch)
	}
}

Popularity 8/10 Helpfulness 4/10 Language go

Source: Grepper

Tags: channel go

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Contributed on Mar 04 2024

Restu Wahyu Saputra

0 Answers Avg Quality 2/10

Go Channel

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go channel

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