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Counting Duplicates

ABS answered on May 30, 2022 Popularity 8/10 Helpfulness 3/10

answer Counting Duplicates

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Counting Duplicates

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function duplicateCount(text){

    let count = 0
    let object ={}

   for(let i of text){
     i = i.toLowerCase()
       if(!object[i]){
        object[i] =1
       }
       else{
           object[i]++
       }
   }
   console.log(object)
   for( let i in object){
    if(object[i] >1){
        count ++
    }
}
   return count
}

Popularity 8/10 Helpfulness 3/10 Language javascript

Source: Grepper

Tags: counting javascript

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Contributed on Jun 24 2022

ABS

0 Answers Avg Quality 2/10

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// Count the number of Duplicates
// Write a function that will return the count of distinct case-insensitive alphabetic characters and numeric digits that occur more than once in the input string. The input string can be assumed to contain only alphabets (both uppercase and lowercase) and numeric digits.

/*
  Example
  "abcde" -> 0 # no characters repeats more than once
  "aabbcde" -> 2 # 'a' and 'b'
  "aabBcde" -> 2 # 'a' occurs twice and 'b' twice (`b` and `B`)
  "indivisibility" -> 1 # 'i' occurs six times
  "Indivisibilities" -> 2 # 'i' occurs seven times and 's' occurs twice
  "aA11" -> 2 # 'a' and '1'
  "ABBA" -> 2 # 'A' and 'B' each occur twice
*/

function duplicateCount(text){
  let duplicateArr = {}, splitText = text.toLowerCase().split('')
  
  splitText.forEach(letter => {
    if(duplicateArr.hasOwnProperty(letter)) duplicateArr[letter] += 1
    else duplicateArr[letter] = 0
  })
  
  const duplicateCount = Object.values(duplicateArr).toString().match(/[1-9]/gm)
  return duplicateCount !== null ? duplicateCount.length : 0
}

// With love @kouqhar

Popularity 8/10 Helpfulness 1/10 Language javascript

Source: www.codewars.com

Tags: javascript counting co

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Contributed on May 30 2022

kouqhar

0 Answers Avg Quality 2/10

Counting Duplicates

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