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javascript Detect Cycle in a Directed Graph

Travinth Dayalaeaswaran answered on July 8, 2022 Popularity 4/10 Helpfulness 2/10

answer javascript Detect Cycle in a Directed Graph

related detect cycle in directed graph javascript

javascript Detect Cycle in a Directed Graph

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<script>
  
// A JavaScript Program to detect cycle in a graph
  
let V;
let adj=[];
function Graph(v)
{
    V=v;
    for (let i = 0; i < V; i++)
        adj.push([]);
}
  
// This function is a variation of DFSUtil() in
    // https://www.geeksforgeeks.org/archives/18212
function isCyclicUtil(i,visited,recStack)
{
    // Mark the current node as visited and
        // part of recursion stack
        if (recStack[i])
            return true;
   
        if (visited[i])
            return false;
               
        visited[i] = true;
   
        recStack[i] = true;
        let children = adj[i];
           
        for (let c=0;c< children.length;c++)
            if (isCyclicUtil(children, visited, recStack))
                return true;
                   
        recStack[i] = false;
   
        return false;
}
  
function addEdge(source,dest)
{
    adj.push(dest);
}
  
// Returns true if the graph contains a
    // cycle, else false.
    // This function is a variation of DFS() in
    // https://www.geeksforgeeks.org/archives/18212
function isCyclic()
{
    // Mark all the vertices as not visited and
        // not part of recursion stack
        let visited = new Array(V);
        let recStack = new Array(V);
        for(let i=0;i<V;i++)
        {
            visited[i]=false;
            recStack[i]=false;
        }
          
           
        // Call the recursive helper function to
        // detect cycle in different DFS trees
        for (let i = 0; i < V; i++)
            if (isCyclicUtil(i, visited, recStack))
                return true;
   
        return false;
}
  
// Driver code
Graph(4);
addEdge(0, 1);
addEdge(0, 2);
addEdge(1, 2);
addEdge(2, 0);
addEdge(2, 3);
addEdge(3, 3);
  
if(isCyclic())
    document.write("Graph contains cycle");
else
    document.write("Graph doesn't "
                   + "contain cycle");
  
  
// This code is contributed by patel2127
  
</script>

Popularity 4/10 Helpfulness 2/10 Language javascript

Source: www.geeksforgeeks.org

Tags: cycle detect directed-graph javascript

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Contributed on Jul 08 2022

Travinth Dayalaeaswaran

0 Answers Avg Quality 2/10

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detect cycle in directed graph javascript

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class Pair {
  constructor(node, par) {
    this.node = node;
    this.par = par;
  }
}

class Sol {
  adj = {};
  vis = [];
  dfsVis = [];
  v = null;

  constructor(v, edges) {
    this.v = v;
    this.vis = Array(v + 1).fill(false);
    this.dfsVis = Array(v + 1).fill(false);

    for (let edge of edges) {
      const u = edge[0];
      const v = edge[1];

      if (!this.adj[u]) {
        this.adj[u] = [];
      }

      this.adj[u].push(v);
    }

    console.log(this.adj);
  }

  detectCycle() {
    for (let i = 1; i <= this.v; i++) {
      if (this.vis[i] === false) {
        if (this.isCycle(i, this.adj, this.vis, this.dfsVis) === true) {
          console.log("Cycle Present");
          return true;
        }
      }
    }

    console.log("Cycle Not Present");
    return false;
  }

  isCycle(s, adj, vis, dfsVis) {
    vis[s] = true;
    dfsVis[s] = true;

    if (adj[s]) {
      for (let nbr of adj[s]) {
        if (vis[nbr] === false) {
          this.isCycle(nbr, adj, vis, dfsVis);
        }

        if (dfsVis[nbr]) {
          return true;
        }
      }
    }

    dfsVis[s] = false;
    return false;
  }
}

const v = 7;
const edges = [
  [1, 2],
  [3, 4],
  [2, 3],
  [4, 1],
];
const s1 = new Sol(4, edges1);
s1.detectCycle();

Popularity 3/10 Helpfulness 1/10 Language javascript

Source: Grepper

Tags: directed-graph javascript detect cycle

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Contributed on Dec 29 2022

Uninterested Unicorn

0 Answers Avg Quality 2/10

javascript Detect Cycle in a Directed Graph

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