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armstrong number in python

Travinth Dayalaeaswaran answered on June 20, 2022 Popularity 10/10 Helpfulness 1/10

answer armstrong number in python

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armstrong number in python

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# Python program to determine whether
# the number is Armstrong number or not
 
# Function to calculate x raised to
# the power y
def power(x, y):
     
    if y == 0:
        return 1
    if y % 2 == 0:
        return power(x, y // 2) * power(x, y // 2)
         
    return x * power(x, y // 2) * power(x, y // 2)
 
# Function to calculate order of the number
def order(x):
 
    # Variable to store of the number
    n = 0
    while (x != 0):
        n = n + 1
        x = x // 10
         
    return n
 
# Function to check whether the given
# number is Armstrong number or not
def isArmstrong(x):
     
    n = order(x)
    temp = x
    sum1 = 0
     
    while (temp != 0):
        r = temp % 10
        sum1 = sum1 + power(r, n)
        temp = temp // 10
 
    # If condition satisfies
    return (sum1 == x)
 
# Driver code
x = 153
print(isArmstrong(x))
 
x = 1253
print(isArmstrong(x))

Popularity 10/10 Helpfulness 1/10 Language python

Source: www.geeksforgeeks.org

Tags: python

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Contributed on Jul 11 2022

Travinth Dayalaeaswaran

0 Answers Avg Quality 2/10

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armstrong python

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def check_if_armstrong():
    number = input("Enter number: ")
    
    sum_of_cube = 0
    for i in range(len(number)):
        sum_of_cube = sum_of_cube + pow(int(number[i]), 3)
    print(sum_of_cube)
    
    if int(number) == sum_of_cube:
        print(f'{number} is armstrong')
    else:
        print(f'{number} isn\'t armstrong')
        
check_if_armstrong()

Popularity 9/10 Helpfulness 4/10 Language python

Source: Grepper

Tags: python py

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Contributed on Jun 20 2022

Suraj Kr Thapa

0 Answers Avg Quality 2/10

armstrong number in python

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