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$array = array(1, 2, 2, 3);
$array = array_unique($array); // Array is now (1, 2, 3)
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let chars = ['A', 'B', 'A', 'C', 'B'];
let uniqueChars = [new Set(chars)];
console.log(uniqueChars);
output:
[ 'A', 'B', 'C' ]
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const myArray = [2,5,6,2,2,4,5,3,3];
const uniqueArray = [new Set(myArray)];
console.log(uniqueArray);
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function onlyUnique(value, index, self) {
return self.indexOf(value) === index;
}
// usage example:
var a = ['a', 1, 'a', 2, '1'];
var unique = a.filter(onlyUnique);
console.log(unique); // ['a', 1, 2, '1']
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let chars = ['A', 'B', 'A', 'C', 'B'];
let uniqueChars = [new Set(chars)];
console.log(uniqueChars);
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function removeDuplicates(arr) {
const map = new Map();
const result = [];
for (const item of arr) {
if (!map.has(item)) {
map.set(item, true);
result.push(item);
}
}
return result;
}
const array = [1, 2, 3, 3, 4, 4, 5];
const uniqueArray = removeDuplicates(array);
console.log(uniqueArray); // Output: [1, 2, 3, 4, 5]
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// Use to remove duplicate elements from the array
const numbers = [2,3,4,4,2,3,3,4,4,5,5,6,6,7,5,32,3,4,5]
console.log([new Set(numbers)])
// [2, 3, 4, 5, 6, 7, 32]
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[new Set(['1','1','2','2','3','3'])]
//this will return a new array with the unique primitive values
//I guess doing this with objects will require implementing equality method.
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let myArray = ['a', 'b', 'a', 'b', 'c', 'e', 'e', 'c', 'd', 'd', 'd', 'd']
let myOrderedArray = myArray.reduce(function (accumulator, currentValue) {
if (accumulator.indexOf(currentValue) === -1) {
accumulator.push(currentValue)
}
return accumulator
}, [])
console.log(myOrderedArray)
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uniq = [new Set(array)];
or
uniqueArray = a.filter(function(item, pos) {
return a.indexOf(item) == pos;
})
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arr.filter((v,i,a)=>a.findIndex(t=>(t.place === v.place && t.name===v.name))===i)