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using ipfn in python

Spotless Swiftlet answered on July 22, 2022 Popularity 1/10 Helpfulness 1/10

answer using ipfn in python

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using ipfn in python

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import numpy as np
from ipfn import ipfn

m = [[40, 30, 20, 10], [35, 50, 100, 75], [30, 80, 70, 120], [20, 30, 40, 50]]
m = np.array(m)
xip = np.array([150, 300, 400, 150])
xpj = np.array([200, 300, 400, 100])

aggregates = [xip, xpj]
dimensions = [[0], [1]]

IPF = ipfn.ipfn(m, aggregates, dimensions, convergence_rate=1e-6)
m = IPF.iteration()
print(m)

Popularity 1/10 Helpfulness 1/10 Language python

Source: github.com

Tags: python using

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Contributed on Jul 22 2022

Spotless Swiftlet

0 Answers Avg Quality 2/10

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using ipfn in python

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import numpy as np
from ipfn import ipfn

m = [[40, 30, 20, 10], [35, 50, 100, 75], [30, 80, 70, 120], [20, 30, 40, 50]]
m = np.array(m)
xip = np.array([150, 300, 400, 150])
xpj = np.array([200, 300, 400, 100])

aggregates = [xip, xpj]
dimensions = [[0], [1]]

IPF = ipfn.ipfn(m, aggregates, dimensions, convergence_rate=1e-6)
m = IPF.iteration()
print(m)

Popularity 1/10 Helpfulness 1/10 Language python

Source: github.com

Tags: python using

Link to this answer
Share Copy Link

Contributed on Jul 22 2022

Spotless Swiftlet

0 Answers Avg Quality 2/10

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using ipfn in python

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