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remove every appearance of char without malloc in c

Mero answered on July 23, 2022 Popularity 1/10 Helpfulness 1/10

answer remove every appearance of char without malloc in c

remove every appearance of char without malloc in c

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void remove_char(char s[], char ch){

    unsigned int strLen = strlen(s);

    // Place ' ' where ch appears
    unsigned int cnt_ch =0 , temp=0;
    int j=0;
    while ( j < strLen ){
        if( s[j] == ch ){
            cnt_ch ++; temp ++; // count number of ch, temp will count if there is more than ch followed by
            // if another char appeared != ch
        }else if ( temp > 0 && s[j] != ch ){

            // assign the current index value to k
            int k = j;

            while ( temp -- ) k --; // reduce k by the number of the appearance of ch

            temp = cnt_ch; // assign back temp = cnt_ch

            s[k] = s[j]; // assign the value of current char to s[k] where ch appears
            s[j] = ' '; // place ' ' instead of the current char
        }
        j++;
    }
    s[strLen - cnt_ch ] ='\0';

    for(char * c= s; *c; c++){
        printf("%c", *c);
    }


}

Popularity 1/10 Helpfulness 1/10 Language c

Source: Grepper

Tags: appearance c char malloc

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Contributed on Jul 23 2022

Mero

0 Answers Avg Quality 2/10

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remove every appearance of char without malloc in c

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