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my_dict = {31: 'a', 21: 'b', 14: 'c'}
del my_dict[31]
print(my_dict)
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dict.pop('key')
#optionally you can give value to return if key doesn't exist (default is None)
dict.pop('key', 'key not found')
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dict = {'an':30, 'example':18}
#1 Del
del dict['an']
#2 Pop (returns the value deleted, but can also be used alone)
#You can optionally set a default return value in case key is not found
dict.pop('example') #deletes example and returns 18
dict.pop('test', 'Key not found') #returns 'Key not found'
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>>> # initialise a dictionary with the keys “city”, “name”, “food”
>>> person1_information = {'city': 'San Francisco', 'name': 'Sam', "food": "shrimps"}
>>> # delete the key, value pair with the key “food”
>>> del person1_information["food"]
>>> # print the present personal1_information. Note that the key, value pair “food”: “shrimps” is not there anymore.
>>> print(person1_information)
{'city': 'San Francisco', 'name': 'Sam'}
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# define a dictionary
my_dict = {'a': 1, 'b': 2, 'c': 3}
# remove a key-value pair from the dictionary
value = my_dict.pop('b')
print(value) #print as 2
print(my_dict) #print as {'a': 1, 'c': 3}
# remove a key-value pair from the dictionary with a default value
value = my_dict.pop('d', None)
print(value) #print as None
print(my_dict) #print as {'a': 1, 'c': 3}
# remove a key-value pair from the dictionary using the `del` statement
del my_dict['a']
print(my_dict) #print as {'c': 3}
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# Python code to demonstrate
# removal of dict. pair
# using del
# Initializing dictionary
test_dict = {"Arushi" : 22, "Anuradha" : 21, "Mani" : 21, "Haritha" : 21}
# Printing dictionary before removal
print ("The dictionary before performing remove is : " + str(test_dict))
# Using del to remove a dict
# removes Mani
del test_dict['Mani']
# Printing dictionary after removal
print ("The dictionary after remove is : " + str(test_dict))
# Using del to remove a dict
# raises exception
del test_dict['Manjeet']
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squares = {1: 1, 2: 4, 3: 9, 4: 16, 5: 25}
# remove a particular item, returns its value
# Output: 16
print(squares.pop(4))