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largest rectangle in histogram java

Itchy Impala answered on August 8, 2022 Popularity 9/10 Helpfulness 1/10

answer largest rectangle in histogram java

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largest rectangle in histogram java

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import java.util.Stack;

public class largestAreaInHistogram {
    private static int largestAreaInHistogram(int[] heights){
        Stack<Integer> st=new Stack<>();
        st.push(-1);
        int maxArea=0;

        //Iterating over the height array for finding the max area.
        for(int i=0;i<heights.length;i++){
            //Height of top element of stack should be greater than current element height
            while(st.size()!=1 && st.peek()!=-1 && heights[st.peek()]>=heights[i]){
                int currheight=heights[st.peek()];
                st.pop();
                //Calculating the width of the rectangle
                int width=i-st.peek()-1;
                //if currheight*width (Area) is greater than previous maxArea
                // then update maxArea
                maxArea=Math.max(maxArea,currheight*width);
            }
            //Pushing each element in stack to calculate area
            st.push(i);
        }
        //Computing area for all the elements left in stack
        while(st.size()!=1){
            int idx=st.pop();
            int w=heights.length-st.peek()-1;
            int h=heights[idx];
            maxArea=Math.max(maxArea,w*h);
        }
        return maxArea;
    }

    public static void main(String[] args) {
        int[] height={5, 6, 4, 3, 7, 5};
        System.out.println("Maximum area is "+largestAreaInHistogram(height));
    }

}

Popularity 9/10 Helpfulness 1/10 Language java

Source: favtutor.com

Tags: histogram java

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Contributed on Aug 08 2022

Itchy Impala

0 Answers Avg Quality 2/10

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largest rectangle in histogram

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#include 
#include 
#include 
#include 
#include  //For using min/max function.
//Above are the libraries that has been used.

using namespace std;

class largestRectangleArea {
public:
    int largestAreaInHistogram(vector<int>& histogram) {
        int n = histogram.size(); //It stores the size of histogram vector.
        if(n == 0) return 0;
        // Create an empty stack. The stack holds indexes of histogram vector.
        stack<int> st;
        st.push(-1);
        int maxarea=0;
        //Iterating over the histogram vector for finding the maximum area.
        for(int i=0;i<n;i++){
            //st.size()>1 because -1 is stored initially and size of stack is 1
            while(st.size()!=1 && histogram[st.top()]>=histogram[i]){
                int len = histogram[st.top()];
                st.pop();
                //computing the width of the rectangle forming in histogram
                int width = i-st.top()-1;
                // if the area (len*width) of the rectangle forming in histogram is greater than previous maxarea then maxarea gets updated to the greater area
                maxarea=max(maxarea,len*width);
            }
            //Pushing index in stack it helps in calculating width
            st.push(i);
        }
        //Calculating area for all the elements left in stack if it is greater than previous maxarea then update maxarea
        while(st.size()!=1){
            int in=st.top();
            st.pop();
            int w = n-st.top() -1;
            int h = histogram[in];
            maxarea = max(maxarea,w*h);
        }
        return maxarea;
    }
};

int main()
{
    vector<int>hist{5, 6, 4, 3, 7, 5};
    largestRectangleArea ob;
    cout << "Maximum area is " << ob.largestAreaInHistogram(hist);
    return 0;
}

Popularity 10/10 Helpfulness 1/10 Language csharp

Source: favtutor.com

Tags: c# c

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Contributed on Aug 08 2022

Itchy Impala

0 Answers Avg Quality 2/10

largest rectangle in histogram java

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