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Longest Substring Without Repeating Characters

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CodeBlack reactor answered on February 17, 2022 Popularity 9/10 Helpfulness 1/10

answer Longest Substring Without Repeating Characters

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Longest Substring Without Repeating Characters

Comment

/*
    Javascript Solution - With Better Performance
    Methods used in this algorithm are:
    1. Two Pointer Technique
    2. Sliding Window Technique
    3. Hash Map

    Time complexity: O(N)
    Space complexity: O(N),
    If the string does not contain repeated characters, 
    then the hash map will contain N characters.
*/

const s = "sdtvtsgh"

const lengthOfLongestSubstring = function(s) {
    let max_length = 0
    let map = {}
    let l = 0

    for (let r = 0; r < s.length; r++) {
        if (map.hasOwnProperty(s[r])) {
            const collision_index = map[s[r]]

            if (collision_index >= l) {
                l = collision_index + 1
            }

            delete map[s[collision_index]]
        }

        if (!map.hasOwnProperty(s[r])) {
            map[s[r]] = r
        }

        if (max_length < (r + 1) - l) {
            max_length = (r + 1) - l
        }

        console.log(map, ':   (', r + 1, '-', l, ')')
    }

    return max_length
}


console.log(lengthOfLongestSubstring(s))

// [Log]:
{ s: 0 } :   ( 1 - 0 )
{ s: 0, d: 1 } :   ( 2 - 0 )
{ s: 0, d: 1, t: 2 } :   ( 3 - 0 )
{ s: 0, d: 1, t: 2, v: 3 } :   ( 4 - 0 )
{ s: 0, d: 1, v: 3, t: 4 } :   ( 5 - 3 )
{ d: 1, v: 3, t: 4, s: 5 } :   ( 6 - 3 )
{ d: 1, v: 3, t: 4, s: 5, g: 6 } :   ( 7 - 3 )
{ d: 1, v: 3, t: 4, s: 5, g: 6, h: 7 } :   ( 8 - 3 )

max_length = 5

Popularity 10/10 Helpfulness 3/10 Language javascript

Source: Grepper

Tags: javascript j

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Contributed on Aug 21 2022

Mysterious Macaque

0 Answers Avg Quality 2/10

longest substring without repeating characters

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/**
 * @param {string} s
 * @return {number}
 */
var lengthOfLongestSubstring = function(s) {
    if (!s.length) return 0

    let left = 0, right = 0
    let maxLength = -Infinity
    const hashSet = {}
    const len = s.length

    while(right < len){
        if (hashSet.hasOwnProperty(s[right])){
            if (hashSet[s[right]] >= left){
                left = hashSet[s[right]]+1
            }
        }
            const lenn = right-left+1
            maxLength = Math.max(lenn, maxLength)
            hashSet[s[right]] = right
            right++
        
    }
    return maxLength

};

Popularity 9/10 Helpfulness 3/10 Language javascript

Source: leetcode.com

Tags: javascript j

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Contributed on Jul 31 2024

Adventurous Alligator

0 Answers Avg Quality 2/10

longest substring without repeating characters

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// JavaScript Solution - Credit to @albertchanged on LC
// Sliding window implementation
var lengthOfLongestSubstring = function(s) {
  if (!s.length) return 0;
  
  let left = 0, right = 0;
  let maxLength = -Infinity;
  const set = new Set();

  while (right < s.length) {
    // If s[right] has not been seen yet
    if (!set.has(s[right])) {
      // Add it to the set
      set.add(s[right]);
      // Increase size of window to right
      right++;
      // Update maxLength; set size represents length of unique substring
      maxLength = Math.max(maxLength, set.size);
    } else {
      // We've seen s[right] so we need to shrink the window
      // Delete s[left] from set
      set.delete(s[left]);
      // Shrink window from left
      left++;
    }
  }

  return maxLength;
}

Popularity 10/10 Helpfulness 3/10 Language javascript

Source: Grepper

Tags: javascript j

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Contributed on Aug 21 2022

Ryan Garcia

0 Answers Avg Quality 2/10

3. Longest Substring Without Repeating Characters

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import java.io.*;
 
class GFG {
    public static int longestUniqueSubsttr(String str)
    {
        String test = "";
 
        // Result
        int maxLength = -1;
 
        // Return zero if string is empty
        if (str.isEmpty()) {
            return 0;
        }
        // Return one if string length is one
        else if (str.length() == 1) {
            return 1;
        }
        for (char c : str.toCharArray()) {
            String current = String.valueOf(c);
 
            // If string already contains the character
            // Then substring after repeating character
            if (test.contains(current)) {
                test = test.substring(test.indexOf(current)
                                      + 1);
            }
            test = test + String.valueOf(c);
            maxLength = Math.max(test.length(), maxLength);
        }
 
        return maxLength;
    }
 
    // Driver code
    public static void main(String[] args)
    {
        String str = "geeksforgeeks";
        System.out.println("The input string is " + str);
 
        int len = longestUniqueSubsttr(str);
        System.out.println("The length of the longest "
                           + "non-repeating character "
                           + "substring is " + len);
    }
}
 
// This code is contributed by Alex Bennet

Popularity 10/10 Helpfulness 3/10 Language java

Source: www.geeksforgeeks.org

Tags: java

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Contributed on Feb 17 2022

Manav Sarkar

0 Answers Avg Quality 2/10

longest substring without repeating characters

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class Solution {
    public int lengthOfLongestSubstring(String s) {int max=0;
        HashMap<Character,Integer>hm=new HashMap<>();
        for(int i=0,j=0;i<s.length();i++){
            if(hm.containsKey(s.charAt(i))){
                j=Math.max(j,hm.get(s.charAt(i))+1);
            }
            hm.put(s.charAt(i),i);
            max=Math.max(max,i-j+1);
        }
        return max;
        
    }
}

Popularity 10/10 Helpfulness 3/10 Language whatever

Source: Grepper

Tags: longest-substring longest-substrin

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Contributed on Aug 22 2022

Nasty Nightingale

0 Answers Avg Quality 2/10

longest substring without repeating characters

Comment

public class Solution 
{
    public int LengthOfLongestSubstring(string str) 
    {
        var dict = new Dictionary<char, int>();
        var max = 0;
        int start = 0;
        for (int i = 0; i < str.Length; i++)
        {
            var x = str[i];
            if (!dict.ContainsKey(x))
            {
                dict.Add(x, 1);
            }
            else
            {
                dict[x] += 1;
                while (start <= i && dict.ContainsKey(str[start]) && dict[x] > 1)
                {
                    dict[str[start]]--;
                    if (dict[str[start]] == 0)
                        dict.Remove(str[start]);
                    start++;
                }
            }
            max = Math.Max(max, i - start + 1);
        }
        return max;
    }
}

Popularity 10/10 Helpfulness 3/10 Language csharp

Source: leetcode.com

Tags: c# c

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Contributed on Jun 10 2022

PrashantUnity

0 Answers Avg Quality 2/10

Longest Substring Without Repeating Characters

Comment

/*
  Given a string s, find the length of the longest substring (A substring is 
  a contiguous non-empty sequence of characters within a string.) 
  without repeating characters.

  Example 1:
  Input: s = "abcabcbb"
  Output: 3
  Explanation: The answer is "abc", with the length of 3.
  
  Example 2:
  Input: s = "bbbbb"
  Output: 1
  Explanation: The answer is "b", with the length of 1.
  
  Example 3:
  Input: s = "pwwkew"
  Output: 3
  Explanation: The answer is "wke", with the length of 3.
  Notice that the answer must be a substring, "pwke" is a subsequence and 
  not a substring.
*/

   const longestStr = s => {
    if(s.length < 2) return s.length

    let [left, right, partial, curIdx, finalLength] = 
        [0, s.length, new Set(), 0, -Infinity]

    while (left < right) {
        partial.add(s[left])

        const curChar = s[left+1]

        // Base case to exit loop early
        if (finalLength > (right - curIdx)) break

        if (partial.has(curChar)) {
            curIdx += 1
            left = curIdx

            partial.size > finalLength ? finalLength = partial.size : null
            partial.clear()
        }else left++

        left === right ? partial.size > finalLength ? 
          finalLength = partial.size : null : null

    }

    return finalLength
  }

  const s = "abcabcbb" // 3
  const res = longestStr(s)
  console.log(res)
    
  /*
	Time Complexity: O(n) (average case)
	Space Complexity: O(n)  
  */

// With love @kouqhar

Popularity 3/10 Helpfulness 2/10 Language javascript

Source: www.linkedin.com

Tags: javascript longest-substring

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Contributed on Nov 07 2024

kouqhar

0 Answers Avg Quality 2/10

json to dart

Comment

class DataDTO {
  String? _name;
  String? _gender;
  int? _age;
  Address? _address;
  List<PhoneNumber>? _phoneNumber;

  DataDTO(
      {String? name,
      String? gender,
      int? age,
      Address? address,
      List<PhoneNumber>? phoneNumber}) {
    if (name != null) {
      this._name = name;
    }
    if (gender != null) {
      this._gender = gender;
    }
    if (age != null) {
      this._age = age;
    }
    if (address != null) {
      this._address = address;
    }
    if (phoneNumber != null) {
      this._phoneNumber = phoneNumber;
    }
  }

  String? get name => _name;
  set name(String? name) => _name = name;
  String? get gender => _gender;
  set gender(String? gender) => _gender = gender;
  int? get age => _age;
  set age(int? age) => _age = age;
  Address? get address => _address;
  set address(Address? address) => _address = address;
  List<PhoneNumber>? get phoneNumber => _phoneNumber;
  set phoneNumber(List<PhoneNumber>? phoneNumber) => _phoneNumber = phoneNumber;

  DataDTO.fromJson(Map<String, dynamic> json) {
    _name = json['name'];
    _gender = json['gender'];
    _age = json['age'];
    _address =
        json['address'] != null ? new Address.fromJson(json['address']) : null;
    if (json['phoneNumber'] != null) {
      _phoneNumber = <PhoneNumber>[];
      json['phoneNumber'].forEach((v) {
        _phoneNumber!.add(new PhoneNumber.fromJson(v));
      });
    }
  }

  Map<String, dynamic> toJson() {
    final Map<String, dynamic> data = new Map<String, dynamic>();
    data['name'] = this._name;
    data['gender'] = this._gender;
    data['age'] = this._age;
    if (this._address != null) {
      data['address'] = this._address!.toJson();
    }
    if (this._phoneNumber != null) {
      data['phoneNumber'] = this._phoneNumber!.map((v) => v.toJson()).toList();
    }
    return data;
  }
}

class Address {
  String? _street;
  String? _city;
  String? _state;
  String? _postalCode;

  Address({String? street, String? city, String? state, String? postalCode}) {
    if (street != null) {
      this._street = street;
    }
    if (city != null) {
      this._city = city;
    }
    if (state != null) {
      this._state = state;
    }
    if (postalCode != null) {
      this._postalCode = postalCode;
    }
  }

  String? get street => _street;
  set street(String? street) => _street = street;
  String? get city => _city;
  set city(String? city) => _city = city;
  String? get state => _state;
  set state(String? state) => _state = state;
  String? get postalCode => _postalCode;
  set postalCode(String? postalCode) => _postalCode = postalCode;

  Address.fromJson(Map<String, dynamic> json) {
    _street = json['street'];
    _city = json['city'];
    _state = json['state'];
    _postalCode = json['postalCode'];
  }

  Map<String, dynamic> toJson() {
    final Map<String, dynamic> data = new Map<String, dynamic>();
    data['street'] = this._street;
    data['city'] = this._city;
    data['state'] = this._state;
    data['postalCode'] = this._postalCode;
    return data;
  }
}

class PhoneNumber {
  String? _type;
  String? _number;

  PhoneNumber({String? type, String? number}) {
    if (type != null) {
      this._type = type;
    }
    if (number != null) {
      this._number = number;
    }
  }

  String? get type => _type;
  set type(String? type) => _type = type;
  String? get number => _number;
  set number(String? number) => _number = number;

  PhoneNumber.fromJson(Map<String, dynamic> json) {
    _type = json['type'];
    _number = json['number'];
  }

  Map<String, dynamic> toJson() {
    final Map<String, dynamic> data = new Map<String, dynamic>();
    data['type'] = this._type;
    data['number'] = this._number;
    return data;
  }
}

Popularity 10/10 Helpfulness 1/10 Language javascript

Source: javiercbk.github.io

Tags: dart

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Contributed on Aug 21 2022

Mert Erkoç

0 Answers Avg Quality 2/10

json to dart

Comment

class Autogenerated {
  int? id;
  int? age;
  String? name;

  Autogenerated({this.id, this.age, this.name});

  Autogenerated.fromJson(Map<String, dynamic> json) {
    id = json['id'];
    age = json['age'];
    name = json['name'];
  }

  Map<String, dynamic> toJson() {
    final Map<String, dynamic> data = new Map<String, dynamic>();
    data['id'] = this.id;
    data['age'] = this.age;
    data['name'] = this.name;
    return data;
  }
}

Popularity 10/10 Helpfulness 1/10 Language javascript

Source: javiercbk.github.io

Tags: dart

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Contributed on Aug 25 2022

anss 5286

0 Answers Avg Quality 2/10

Longest Substring Without Repeating Characters

Comment

class Solution {

    /**
     * @param String $s
     * @return Integer
     */
    function lengthOfLongestSubstring($s) {
        
    }
}

Popularity 9/10 Helpfulness 1/10 Language php

Source: Grepper

Tags: longest-substring longest-substrin

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Contributed on Aug 17 2022

CodeBlack reactor

0 Answers Avg Quality 2/10

Longest Substring Without Repeating Characters

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Longest Substring Without Repeating Characters

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Longest Substring Without Repeating Characters

longest substring without repeating characters

longest substring without repeating characters

3. Longest Substring Without Repeating Characters

longest substring without repeating characters

longest substring without repeating characters

Longest Substring Without Repeating Characters

json to dart

json to dart

Longest Substring Without Repeating Characters

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